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Anton [14]
4 years ago
10

What is the density of a 2 gallon milk jug that has a mass of 2.0 kg? Answer should be in g/ml.

Physics
1 answer:
kirill [66]4 years ago
8 0

volume of milk is given as

V = 2 Gallon

we will convert it into mL unit

V = 2 Gal = 7570.82 ml

mass of the milk m = 2kg

m = 2000 g

now for the density we can use

\rho = \frac{m}{V}

\rho = \frac{2000}{7570.82}

\rho = 0.264 g/mL

<em>so the density is 0.264 g/mL for above sample</em>

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The best answer between the two options would be the second choice B) FALSE.
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3 years ago
A student jumps off a sled toward the NORTH after it stops at the bottom of an icy hill. Based on Newton's third law of motion,
zhuklara [117]

When the student the sled jumps off toward the north , the sled most likely move towards the south.

<h3>What is the Newton third law?</h3>

According to the Newton third law of motion, action and reaction are equal and opposite. This means that the direction of the reaction force must also be opposite to that of the action.

As such, when the student the sled jumps off toward the north , the sled most likely move towards the south.

Learn more about Newton third law:brainly.com/question/974124

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8 0
2 years ago
3 a There is a thin layer of water between the blade and the ice. Suggest how this affects friction .​
Gelneren [198K]

Answer:

The water acts like a lubricant therefore has a smooth motion over the ice.

8 0
3 years ago
An object whose specific gravity is 0.850 is placed in water. What fraction of the object is below the surface of the water?
Fynjy0 [20]

Answer:

The fraction of the object that is below the surface of the water is ¹⁷/₂₀

Explanation:

Given;

specific gravity of the object, γ = 0.850

Specific gravity is given as;

specific \ gravity = \frac{density \ of the \ object}{density \ of \ water}\\\\0.85= \frac{density \ of the \ object}{1000 \ kg/m^3} \\\\density \ of the \ object = 850 \ kg/m^3

Fraction of the object's weight below the surface of water is calculated as;

= \frac{850}{1000} \ \times\ 100\%\\\\= 85 \% \\\\= \frac{17}{20}

Therefore, the fraction of the object that is below the surface of the water is ¹⁷/₂₀

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3 years ago
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The energy carried by a single photon of frequency f is given by:
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where h=6.6 \cdot 10^{-34} m^2 kg s^{-1} is the Planck constant. In our problem, the frequency of the photon is f=7.15 \cdot 10^{14}Hz, and by using these numbers we can find the energy of the photon:
E=(6.6\cdot 10^{-34}m^2 kg s^{-1})(7.15 \cdot 10^{14}Hz)=4.7 \cdot 10^{-19}J
4 0
3 years ago
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