Osmium atomic number is 76
The balanced equation for the above reaction is as follows;
Na₂SO₄ + BaCl₂ --> BaSO₄ + 2NaCl
Na₂SO₄ reacts with BaCl₂ in the molar ratio 1:1
Number of Na₂SO₄ moles - 10.0 g / 142.1 g/mol = 0.0704 mol
Number of BaCl₂ moles - 10.0 g / 208.2 g/mol = 0.0480 mol
this means that 0.0480 mol of each reactant is used up, BaCl₂ is the limiting reactant and Na₂SO₄ has been provided in excess.
stoichiometry of BaCl₂ to BaSO₄ is 1:1
number of BaSO₄ moles formed - 0.0480 mol
Mass of BaSO₄ - 0.0480 mol x 233.2 g/mol = 11.2 g
theoretical yield is 11.2 g but the actual yield is 12.0 g
the actual product maybe more than the theoretical yield of the product as the measured mass of the actual yield might contain impurities.
percent yield - 12.0 g/ 11.2 g x 100% = 107%
this is due to impurities present in the product or product could be wet.
Answer:
0.525 M CuSO
Explanation:
Molarity (M) is the units mol/L. Let's figure out how many moles of CuSO we have:
35 mL = 35/1000 L = 0.035 L
0.035 L * 1.50 mol/L = 0.0525 mol CuSO
Our new volume is 100 mL, so let's first convert this to L:
100 mL = 100/1000 L = 0.100 L
To find the new molarity, divide the number of moles (0.0525 moles) by the number of liters (0.100 L):
0.0525 mol / 0.100 L = 0.525 M CuSO
Hope this helps!
