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Leokris [45]
3 years ago
5

For this experiment you want to prepare a 0.10 m solution of sodium hydroxide. how many grams of sodium hydroxide must be added

to give you 500.0 ml of that solution? question 1 options:
Chemistry
1 answer:
Degger [83]3 years ago
7 0
c×v
n (NaOH) = ------
1000

0.1 × 500
n (NaOH) = ----------------
1000
n (NaOH) = 0.05 moles

Mass= Mr(NaOH) × moles
Mass= (23+16+1) × 0.05
Mass=2.15 g (2.15 grams)
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Which of the following is not a characteristic of a metal?
jolli1 [7]

Answer:

B. Poor conductor.

Explanation:

It cannot be A, as only 1 metal is not solid at room temp.

It cannot be C, as most metals are ductile.

It cannot be D, as most metals are malleable.

This leaves B, which is not true about metals, as a lot are very good conductors.

3 0
2 years ago
Calculate: The molecular mass of a molecule is the sum of the masses of each atom in the molecule. The
Charra [1.4K]

Answer:

44.01

Explanation:

12.01 + 16.00 + 16.00 = 44.01

4 0
3 years ago
Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:
AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

1)

Mass of  Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

2)

Mass of  Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

3)

Mass of  Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

4)

Mass of  Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu

The average mass of iron to be is 54.76 amu.

5 0
3 years ago
NH3 + HCI —> NH4CI synthesis O decomposition O single replacement O double replacement​
wlad13 [49]

Answer:

synthesis

Explanation:

The reaction given is a synthesis reaction or combination reaction.

Given equation:

                        NH₃  +  HCl   →   NH₄Cl

In a synthesis reaction, a single product is formed from two or more reactants

                          A + B →  C

The formation of compounds from the union of constituent elements also falls into this category.

So the given reaction is a synthesis reaction.

In a decomposition reaction two or more products are formed from a single reactant

In a single replacement reaction, one substance replaces another.

In double replacement reactions partners in a chemical specie are exchanged.

Therefore the given reaction is a synthesis reaction

8 0
3 years ago
The very common mineral shown in this photograph is commonly a pink- to cream-colored mineral with wavy, light-colored lines. it
musickatia [10]
The very common mineral shown in the figure that is referred in this problem that is commonly a pink- to cream-colored mineral with wavy, light-colored lines and does not effervesce would be feldspar. It make up about 41 percent weight of the Earth's crust. It is a group of rocks that contains tectosilicate compounds.
8 0
3 years ago
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