Answer:
73.4% is the percent yield
Explanation:
2KClO₃ → 2KCl + 3O₂
This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.
We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃
In the theoretical yield of the reaction we say:
2 moles of potassium chlorate can produce 3 moles of oxygen
Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂
The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g
But, we have produced 115 g. Let's determine the percent yield of reaction
Percent yield = (Produced yield/Theoretical yield) . 100
(115g / 156.6g) . 100 = 73.4 %
Answer:
the number of laps in the case when he run for 50 minutes is 18,333.33
Explanation:
The computation of the number of laps in the case when he run for 50 minutes is shown below:
Given that
He runs 440m lap in 1.2 minutes
So in 50 minutes he can have laps of
= 440 × 50 ÷ 1.2
= 18,333.33 laps
hence, the number of laps in the case when he run for 50 minutes is 18,333.33
K2S (aq) + CoCl2( aq) -----> 2KCl (aq) + CoS (s)
potassium + cobalt potassium chloride + carbonyl sulfide
sulfide chloride
carbonyl sulfide :- it is chemical compound with linear formula (OCS ) normally written as (CoS) .it does not show its structure . its is colorless flammable gas with an unpleasant odour.
Potassium chloride :- It is metal halide salt composed of potassium and chlorine. it is odorless and has white or colorless crystal appearance <span />
Answer:
of water at 30C and 1 atm is 256.834 J/mol·K.
Explanation:
To solve the question, we note the Maxwell relation such as

Where:
= Specific heat of gas at constant pressure = 75.3 J/mol·K
= Specific heat of gas at constant volume = Required
T = Temperature = 30 °C = 303.15 K
α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹
K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹
Therefore,
75.3 -
= 
=
- 75.3 = 256.834 J/mol·K.
The two reason behind the invalidity of flame test are false positive and false negative.
while performing the flame test you must have to be accurate otherwise you will get false results may be positive for some element or may be negative in case the element is present. The main reason to get the false positive and false negative is the presence and contamination of sodium.