Marc wishes to invest in a stock with a 10% return annually. How much money will he have at the end of the year
1 answer:
Answer:
At the end of the year, Marc will have 1.10 times the amount invested
Step-by-step explanation:
Let
x -----> the amount that Marc wishes to invested
Remember that
At the end of the year the amount of money will be the amount invested multiplied by 1.10
so
1.10x
therefore
At the end of the year, Marc will have 1.10 times the amount invested
<em>Alternative Method</em>
we know that
The simple interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have
substitute in the formula
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Answer:
The area of the quadrilateral B-H-G-E is 7
Step-by-step explanation:
The area of the parallelogram = 60
It can be shown that ΔG-D-F = 3/10 × Area of the parallelogram S = 3/10×S
Because the diagonal B-D shares A-F into the ratio 1:2, the ΔH-D-A = 2/3×ΔD-B_A where ΔD-B_A = 1/2·S, therefore, ΔD-B_A = 2/3×1/2×S = 1/3×S
ΔB-F-H is similar to ΔD-B_A scaled to 1/2,
Therefore;
The area of ΔB-F-H = 1/4×Area of ΔD-B_A = 1/4×1/3×S = 1/12×S,
ΔF-C-D = 1/4×S
ΔE-A-D = 1/4×S
The area of the quadrilateral B_H_G_E found as follows;
Area B_H_G_E = S - (ΔF-C-D + ΔG-D-F +ΔE-A-D +ΔB-F-H)
Area B_H_G_E = S - (1/4×S + 1/10×S +1/4×S +1/12×S) = S - 53/60×S = 7/60×S
Whereby we are given that the area, S of the parallelogram AB-CD = 60 we have;
Area B_H G_E = 7/60×60 = 7
