Answer: A volume of 600 mL of 3.0 M 
solution can be prepared by using 100.0 mL OF 18 M .
Explanation:
Given: 
= ?, 
, 
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 600 mL of 3.0 M solution can be prepared by using 100.0 mL OF 18 M .
Answer:
yes
Explanation:
the metallic properties of elements tends to decrease across a period and increase down a group.
Answer:
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A gallon of water weighs 8.34 pounds
Number of atoms = moles of magnesium x 6.02x10^23
= 5x6.02x10^23
= 3.01x10^24 atoms.
Hope this helps!
