Answer:
We have to fill the acetylene tank with a pressure of 60.67 atm to ensure that you run out of each gas at the same time
Explanation:
Step 1: Data given
Volume of tank 1 = 6.50 L = oxygen
Volume of tank 2 = 4.50 L = acetylene
Pressure in the oxygen tank = 105 atm
Step 2: The balanced equation
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
For 2 mol C2H2 we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O
Step 3: Calculate the pressure of the acetylene tank
For 2 mol C2H2 we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O
This means for each 5 moles O2 we have 2 moles acetylene
Pressure (105 atm) * (2/5) * (6.50 / 4.50) = 60.67 atm
We have to fill the acetylene tank with a pressure of 60.67 atm to ensure that you run out of each gas at the same time
Explanation:
pls the question is not clear to me
Answer:
The ratio 35Cl/37Cl = 3/1
Explanation:
<u>Step 1:</u> Data given
Chlorine has 2 isotopes:
- mass = 35 g/mol
- mass = 37 g/mol
Average molar mass of chlorine = 35.5 grams
<u>Step 2: </u>Calculate the % of isotopes
35x + 37y = 35.5
x+y = 1 or x = 1-y
35(1-y) + 37y = 35.5
35-35y +37y = 35.5
0.5 = 2y
y = 0.25 = 37Cl
x = 1 - 0.25 = 0.75 = 35Cl
<u>Step 3: </u>
The ratio 35Cl/37Cl = 0.75/0.25 = 3/1
Isolate the lab immediately mercury can be easily tracked throughout a lab by people walking on spill. laboratory staff can safely clean up small spill . don't stamp on small pieces . carefully inspect the bench tops and floors before sitting. to avoid hurting .
