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3 years ago

How much does a gallon of water WEIGH?

Chemistry

1 answer:

elixir [45]3 years ago

4 0

A gallon of water weighs 8.34 pounds

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If an atom with a mass of 47 amu has 22 neutrons, what atom is it?

LenaWriter [7]

Answer:

Manganese

Explanation:

At Mass - No neutrons = Atomic Number = #protons in nucleus

47 - 22 = 25 => At. No. 25 is Manganese (Mn)

7 0

2 years ago

Can someone help me please :)

Fudgin [204]

I think it’s the third option but I’m not entirely sure

3 0

2 years ago

Read 2 more answers

Will mark the brainiest later for correct answers! Please show work.

Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

a. moles in 14.08 g of $C_{12}H_{22}O_{11}$ = $\frac{14.08g}{342.3g/mol}=0.04113moles$

molecules in 14.08 g of $C_{12}H_{22}O_{11}$ = $0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}$

b. moles in 17.75 g of NaCl = $\frac{17.75g}{58.5g/mol}=0.3034moles$

molecules in 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

formula units 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

c. moles in 20.06 g of $CuSO_4.5H_2O$ = $\frac{20.06g}{249.68g/mol}=0.08034moles$

formula units in 20.06 g of $CuSO_4.5H_2O$ = $0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}$

7 0

2 years ago

In at least 4 sentences, explain how access to technology may have an impact to what energy sources are used? THINK- industriali

larisa [96]

Answer : attention swung away from renewable sources as the industrial revolution ... turbines have developed greatly in recent decades, solar photovoltaic technology is ... However, the variability of wind and solar power does not correspond with ... and 0.17 for solar PV, hence declared net capacity (DNC) is the figure

Explanation:

8 0

2 years ago

a quantity of gas has a volume of 400.0 mL when confined under a pressure of 600.0mm Hg. what will be the new volume of the gas

Alex787 [66]

Answer:

1200 mL

Explanation:

Given data

Initial pressure (P₁): 600.0 mmHg

Initial volume (V₁): 400.0 mL

Final pressure (P₂): 200.0 mmHg

Final volume (V₂): ?

For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.

$P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL$

3 0

2 years ago