How does changing the amount of copper wire affect an electromagnet’s strength?

1 answer:

6 0

Answer:copper is the #1 electricity conducter in the world say you have 20,000 volts you would have to have a decent size piece of copper which means the higher the voltage the thicker the copper has to be

Explanation:

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A resistor, capacitor, and switch are all connected in series to an ideal battery of constant terminal voltage. Initially, the s

erma4kov [3.2K]

Answer:

The voltage across the resistor is zero, and the voltage across the capacitor is equal to the terminal voltage of the battery.

Explanation:

This is because when a capacitor is charged no current or voltage flows through it so it will have a voltage equal to the terminal voltage of the battery

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3 years ago

Any push or pull on an object is Question 5 options: Acceleration Velocity Force Inertia

Kobotan [32]

This would be force. Acceleration is increasing the speed in an object and velocity is how fast an object is going. Also, inertia basically says that an object will stay at rest or in motion unless an outside force acts on it. So, for example, a ball will stay in the air unless gravity acts on it and pulls it down. By definition, force is any action, unopposed (or by itself without any other forces that would do the opposite) will change the motion of an object, so this definitely makes the most sense for the question. Hope this helps!

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3 years ago

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9. A sports car travels on a straight road at 22.0 km/h and increases its speed to 57.0 km/h in

Varvara68 [4.7K]

Answer:

4.4 M/s

Explanation:

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3 years ago

Your teacher (175kg) and the lab (15kg) are 2m apart. What is the gravitational force between them? Draw a FBD, and label

Pachacha [2.7K]

The gravitational force between two objects is given by
$F=G \frac{m_1 m_2 }{r^2}$
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

In this problem, $m_1 = 175 kg$ , $m_2 =15 kg$ and $r=2 m$ , therefore the gravitational force between the two objects is
$F=(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}) \frac{(175 kg)(15 kg)}{(2m)^2}=4.38 \cdot10^{-8} N$

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3 years ago

A train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s2. What is the final velocity of the train?

alexandr1967 [171]

Answer:

Final speed of the train is 7.5 m/s

Explanation:

It is given that,

Uniform acceleration of the train is, a = 1.5 m/s²

It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :

$v=u+at$