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Fynjy0 [20]
3 years ago
10

You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 28.4 NN . If you t

hen lower the statue into a tub of water, so that it is completely submerged, the scale reads 17.0 NN .
Physics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

2491.23 kg/m³

Explanation:

From Archimedes principle,

R.d = weight of object in air/ upthrust in water = density of the object/density of water

⇒ W/U = D/D' ....................... Equation 1

Where W = weight of the ceramic statue, U = upthrust of the ceramic statue in water, D = density of the ceramic statue, D' = density of water.

Making D the subject of the equation,

D = D'(W/U).................... Equation 2

Given: W = 28.4 N, U = lost in weight = weight in air- weight in water

U = 28.4 - 17.0 = 11.4 N,

Constant: D' = 1000 kg/m³.

Substitute into equation 2,

D = 100(28.4/11.4)

D = 2491.23 kg/m³

Hence the density of the ceramic statue = 2491.23 kg/m³

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The concave mirror is a spherical-shaped mirror that has an inner curved surface. Hence, option (4) is correct.

What is a concave mirror?

The concave mirrors are spherical-shaped mirrors that are painted on the outward surface. It is also known as the converging mirror, having the recessed inner reflecting surface.

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  • The reflecting surface of the concave mirror has its vertex or midpoint lying farther away from the objects than the edges.

Thus, we can conclude that the surface of the concave mirror is curved inward. Hence, option (4) is correct.

Learn more about the concave mirror here:

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2 years ago
Rocks in the Earth's mantle contain a higher percentage of _______ and _______ than do rocks in the Earth's crust.
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Give reason for the following observation
Irina-Kira [14]

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hope this helps

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3 years ago
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Planet-X has a mass of 3.42×1024 kg and a radius of 8450 km. What is the First Cosmic Speed i.e. the speed of a satellite on a l
tino4ka555 [31]

Answer:

First cosmic speed = 5195.74m/s

Second cosmic speed = 7346.05m/s

The raduis of the synchronous 0rbit of satellite is 2.80×10^7m

Explanation:

The first cosmic speed Is determined using the Orbital speed equation which is given by:

V = Sqrt(GM/r)

Where G = gravitational constant = 6.67 ×10^-11

M = Mass of planet

r = radius of the planet

V = Sqrt (6.67×10^-11)(3.42×10^24)/(8450×10^3)

V = Sqrt (2.28×10^14)/(8450×10^3)

V = Sqrt ( 26995739.64)

V = 5195.75m/s

The second cosmic speed is given by :

V = Sqrt(2 × GM)/r

V = Sqrt (2 × (6.67×10^-11)(3.42×10^24)/(8450×10^3)

V = Sqrt( 4.5×10^14)/ (8450×10^3)

V = Sqrt(53964497.04)

V = 7346.05m/s

The raduis of the synchronous orbit if the satellite around the planet is given by:

r = Cuberoot(T^2GM/4 pi r^2where T is the period of rotation of the planet in second

Given :

T = 17.1 hours converting to seconds

T = 17.1 ×60 ×60 = 61560 seconds

Substituting into the equation

r = Cuberoot ([(61560)^2×(6.67×10^-11)(3.42×10^24)/ (4 ×3.142×r^2)]

r = 2.80×10^7m

5 0
3 years ago
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A 25 cm diameter circular saw blade spins at 3500 rpm. How fast would you have to push a straight hand saw to have the teeth mov
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Answer:

The answer is "45.79 m/s"

Explanation:

Given values:

diameter= 25 cm

w= 3500 rpm

Formula:

\boxed{v=w \times r} \ \ \ \ \ \ _{where}  \ \ \ w  =  \frac{rad}{s}  \ \ \ and  \ \ \ r   = meters

Calculating r:

r= \frac{diameter}{2}

  =\frac{25}{2}\\\\=12.5 \ cm

converting value into meters: 12.5 \times 10^{-2} \ \ meter

calculating w:

w= diameter \times \frac{2\pi}{60}\\

   = 3500 \times \frac{2\times 3.14}{60}\\\\= 3500 \times \frac{2\times 314}{6000}\\\\= 35 \times \frac{314}{30}\\\\= 35 \times \frac{314}{30}\\\\=\frac{10990}{30}\\\\=\frac{1099}{3}\\\\=366.33

w= 366.33 \ \ \frac{rad}{s}

Calculating v:

v= w\times r\\

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