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3 years ago

What is the theory of the beginning of the Universe?

Physics

1 answer:

Black_prince [1.1K]3 years ago

5 0

Hi!The theory of the begining of the universe is the big bang theory

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Compare the percent change in angular momentum of the system to the percent change in the rotational kinetic energy of the syste

Lapatulllka [165]

Answer:

change in the angular momentum gives a greater change in the kinetic energy since it has a quadratic dependence with the angular velocity

Explanation:

Let's write the definition of angular momentum

L = I w

the kinetic energy is

K = ½ I w²

w = L / I

we substitute

K = ½ I L² / I²

K = L² / 2I

K / L = w / 2

therefore a change in the angular momentum gives a greater change in the kinetic energy since it has a quadratic dependence with the angular velocity

8 0

3 years ago

Which feature of electromagnets makes them more useful than permanent

mezya [45]

I think it’s D................

4 0

3 years ago

In order to increase the efficiency of the detection-to-engagement sequence, one can never have too much information from sensor

Elan Coil [88]

Answer:

False

Explanation:

Much information can be gotten from sensor due to the much data being gathered.

7 0

3 years ago

In a crude model of a rotating diatomic molecule of chlorine (Cl2), the two Cl atoms are 2.00 ✕ 10-10 m apart and rotate about t

Troyanec [42]

Answer:

$1.03723\times 10^{-20}\ J$

Explanation:

r = Radius of atom = $1\times 10^{-10}\ m$

m = Mass of chlorine atom = $5.88\times 10^{-26}\ kg$

$\omega$ = Angular speed = $4.2\times 10^{12}\ rad/s$

The moment of inertia of the system is given by

$I=2mr^2\\\Rightarrow I=2\times 5.88\times 10^{-26}\times (10^{-10})^2\\\Rightarrow I=1.176\times 10^{-45}\ kgm^2$

Kinetic energy is given by

$K=\dfrac{1}{2}I\omega^2\\\Rightarrow K=\dfrac{1}{2}\times 1.176\times 10^{-45}\times (4.2\times 10^{12})^2\\\Rightarrow K=1.03723\times 10^{-20}\ J$

The rotational kinetic energy of one molecule of the atom is $1.03723\times 10^{-20}\ J$

7 0

3 years ago

The temperature coefficient of a certain conducting material is 5.74 × 10-3 (°C)-1. (a) At what temperature would the resistance

Alex777 [14]

Answer:

Temperature at which the resistance is twice the resistance at $20^{\circ}C$ is $194.216^{\circ}C$

Solution:

As per the question:

Temperature coefficient, $\alpha = 5.74\times 10^{- 3}^{\circ}C$

Reference temperature, $T_{o} = 20^{\circ}C$

Resistance, $R_{t} = 2R_{o}$

Now, using the formula:

$R_{t} = R_{o}(1 + \alpha \Delta T)$

$2R_{o} = R_{o}(1 + \alpha \times (T _ T_{o}))$

$2 = 1 + 5.74\times 10^{- 3}\times (T - 20^{\circ})$

$\frac{1}{5.74\times 10^{- 3}} = T - 20^{\circ}$

$T = 174.216 + 20 = 194.216^{\circ}$

Yes, this temperature holds for all all the conductors of copper, irrespective of the size and shape of the conductor.

5 0

3 years ago

What is the theory of the beginning of the Universe?​

What is the theory of the beginning of the Universe?