1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
10

Explain how do you know that 712 is greater than 1/3 but less than 2/3

Mathematics
1 answer:
Rudik [331]3 years ago
5 0

Answer:

712 is bigger than 1/3 and 2/3.

Step-by-step explanation:

Because it is whole number, while 1/3 and 2/3 are fraction of whole number.

Did you mean 7/2?

You might be interested in
What are the female reproductive glands called?
adelina 88 [10]
Ovaries. That's were the eggs are held waiting for the sperm to arrive.
6 0
3 years ago
Read 2 more answers
For triangles Y Z X and C D B, sides Y Z, Z X, C D, and B D are 2.5 centimeters. Sides B C and Y X are 3.8 centimeters. Angles B
zmey [24]

Answer:

the answer is C

Step-by-step explanation:

edge 2021

3 0
3 years ago
Read 2 more answers
The difference between one-fifth of a number and 4 is -75
Varvara68 [4.7K]
Think of this as (1/5)x - 4 = -75, where x is the number that we are trying to figure out. To figure this out, we want to get x by itself, so we can go:

(1/5)x=-71
x=-71*5
x=-355

So your number is -355
7 0
3 years ago
"Quadrilateral BCDE is inscribed in circle A as shown in the picture.<br> What is m∠E? "
Veseljchak [2.6K]
96 Degrees.You need to find the length of the arcs outside by multiplying the inside angles by 2. That number must go with the arcs that are enclosed.
7 0
3 years ago
Read 2 more answers
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
Other questions:
  • Answers are appreciated! :D
    15·1 answer
  • LOOK AT THE PICTURE I NEED THIS DONE ASAP PLEASE HELP ME!!!
    6·1 answer
  • Estimate 49.419-27.276 by first rounding each number to the nearest thousand.
    14·1 answer
  • Please help idk know how to find x
    10·1 answer
  • Need a correct answer please
    5·1 answer
  • 7x - 4 = 24<br> show your work
    6·2 answers
  • Una muestra aleatoria si 136 personas de 400 a quien se le aplica un nuevo medicamento experimentaron mejoría Desarrolla un inte
    10·1 answer
  • X=3 y=5 z=-2<br> Please help me with number 10
    13·2 answers
  • PLEASE ANSWER ASAP FOR BRAINESLT!!!!!!!!!!!!!!!!!!
    15·2 answers
  • Your school day begins at 8:50 a.m. and ends at 3:10 p.m. How long are you in school?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!