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3 years ago

Expression is equivalent to 52 + 33?

Mathematics

2 answers:

nlexa [21]3 years ago

8 0

52 + 33 = 85

80 + 5

Answer: 80 + 5

sineoko [7]3 years ago

3 0

Lets first solve this:-

52 + 33 = 85

Now we need to find something equivalent to this. We can work it out like this:-

33 - 3 = 30
52 + 3 = 55

30 + 55 = 85

So, 52 + 33 = 30 + 55.

Hope I helped ya!! xD

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Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zigmanuir [339]

Answer:

$P(E \cup F)=P(E)+P(F)$ .

Step-by-step explanation:

Given the statement

If $P(E)+P(F)=P(E \cup F)+P(E \cap F)$ , then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

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Step-by-step explanation:

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3 years ago

If x is equal to -6 which equality is true

Papessa [141]

Answer:

-5 - 3x > 10

Step-by-step explanation:

x = -6

Plug in the x value for each inequality:

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True

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27 < -14

False

1 - 2(-6) > 13

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Only one of these is true; that is the answer.

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3 years ago

A student’s score on an exam is an integer between 0 and 100. A score of 90 to 100 is an A, 80 to 89 is a B, 70 to 79 is a C, 60

elixir [45]

Answer:

A. 0.22

B. 0.18

C. 0.25

D. 0.244

Step-by-step explanation:

S = {51 to 100} = 50

The sample space S contains values from 51 to 100 which is a total of 50 different values.

Probability of A (lies between the values of 90 to 100 = 11).

11/50 = 0.22

For a student to fail the course, his course has to be less than 60 = from 51 to 59. A total of 9 values.

9/50 = 0.18

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P(student did not get C) = 1-0.20 = 0.80

To get B, ( 80 to 89)

10/50 = 0.20

Probability that a student who is known not to have a c grade has a b grade = 0.20/0.80 = 0.25

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41/50 = 0.82

Probability of student who passed having a B = 0.20/0.82 = 0.244

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Answer:

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