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3 years ago

Constructive interference occurs when waves meet. .

2 answers:

6 0

Answer:Constructive interference occurs whenever waves come together so that they are in phase with each other. This means that their oscillations at a given point are in the same direction, the resulting amplitude at that point being much larger than the amplitude of an individual wave.

Explanation: your answer should be C i guess.

alukav5142 [94]3 years ago

6 0

Constructive interference occurs when the crest of one wave meets the crest of another wave and hence, a higher amplitude wave is formed.

Answer: Option D

<u>Explanation: </u>

According to the superposition principle, a constructive interference occurs when more than two waves of same kind meets at the same points, then the resultant wave amplitudes are equal to vector sums of the amplitude of all the individual waves.

When crest of a wave meets the crests of another wave, or likewise, the trough or a wave meets the trough of other wave, a higher amplitude wave is formed which is known as a constructive wave. And, when a crest of a wave reaches the trough, a lower amplitude wave is formed which is known as destructive wave.

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Suppose that the metal cylinder in the last problem has a mass of 0.10 kg and the coefficient of static friction between the sur

andrew11 [14]

Answer:

The speed maximum speed is $0.49ms^{-1}$

Explanation:

The centrifugal force always acts on the cylinder and move away the rotating platform from the rotational axis. so the centripetal force provide by the frictional force:

Therefore

$\frac{mv^{2} }{r} =u_{s} mg$

coefficient of static friction: $u_{s} =0.12$

mass of the cylinder: $m=0.10kg$ \

distance of the cylinder from the turntable: $r=0.20m$

$\frac{mv^{2} }{r} =u_{s} mg$

cross multiply to find v

$v^{2} =u_{s} rg\\v=\sqrt{u_{s}rg } \\v=\sqrt{0.12*0.20*9.80}\\ v=0.49m/s$

4 0

3 years ago

Read 2 more answers

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bezimeni [28]

Answer:

its a liquid

Explanation:

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8 0

3 years ago

In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.

garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

$\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...$

Find the equivalent resistance of the right branch of the circuit:

$R_{eq} = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms$

$\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411$

6 0

2 years ago

State newtons third law of motion,and give an example that shows how this law works

julsineya [31]

his third law is for every action, there is an equal and opposite reaction. For example when you throw a ball on the floor, it bounces back up. The action is throwing the ball and the reaction is the ball bouncing back up.

6 0

3 years ago

The displacement vector from your house to the library is 520 m long, pointing 40 ∘ north of east.What are the x-component (x-ax

Alexeev081 [22]

Answer:

398.3 m, 334.2 m

Explanation:

The magnitude of the displacement vector is

v = 520 m

And its direction is

$\theta=40^{\circ}$