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3 years ago

2. How long will it take for a ball thrown vertically upward with an initial velocity of

Physics

1 answer:

KengaRu [80]3 years ago

6 0

Answer:

13.33 seconds

Explanation:

At maximum height, the equation of motion becomes:

v = u + at

Since the object was thrown vertically, the initial velocity (u) is zero and the acceleration (a) becomes the acceleration due to gravity (10 m/s2). The equation becomes:

v = at

v = 480 km/hr = 133.333 m/s

10t = 133.333

t = 133.333/10

t = 13.33 seconds.

The time for the ball thrown vertically with a velocity of 480 km/hr to reach the maximum height is 13.33 seconds.

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A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision.

IgorLugansk [536]

Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

$(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}$

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v₁ = velocity of the car = 10 [m/s]

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v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

$(1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]$

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Options 1 and 5 are correct

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