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erastovalidia [21]

3 years ago

13

Standing at the same location, which organism would have the GREATEST gravitational attraction to the earth?

2 answers:

Nastasia [14]3 years ago

7 0

To claculate the gravitational attraction between two bodies with mass 1(m1) and mass 2 (m2) you need to use the equation:

F= G ((m1*m2)/r^2)

Where;
G is the gravitational constant (6.67E-11 m^3 s-2 Kg-1) and
r is the distance between the two objects.

Anestetic [448]3 years ago

6 0

your pet elephant

why because elephant has more mass than any of your answer choice in your question even tho you didn't drop down any answer choice.

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An object is dropped from a height of 25 meters. At what velocity will it hit the ground? A. 7.0 meters/second B. 11 meters/seco

Basile [38]

$Final^{2}=Initial^{2}+2ad \\ x^{2}=0^{2}+2(9.8)(25) \\ x^{2}=490 \\ x=22.13 \\ C$

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Gnesinka [82]

Answer:

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Explanation:

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2 years ago

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Which of these is not true about the proton?

bulgar [2K]

Answer:

Option C is the untrue statement.

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3 years ago

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s344n2d4d5 [400]

Answer:

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3 years ago

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A fairground ride consists of a large vertical drum that spins so

expeople1 [14]

Answer:

v = 3.84 m/s

Explanation:

In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:

$Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}$

where,

v = minimum speed = ?

g = acceleration due to gravity = 9.81 m/s²

r = radius = 10 m

μ = coefficient of friction = 0.15

Therefore,

$v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}$

<u>v = 3.84 m/s</u>

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3 years ago