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Svetlanka [38]
3 years ago
15

What are the 3 tools used to collect weather data

Physics
1 answer:
sergey [27]3 years ago
5 0
Anemometer, Psychrometer, <span>Barometer</span>
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Four main types of resistant forces
kondaur [170]
Applied Force, Gravity Force, Normal Force, Friction Force, Air Resistance Force, Tension Force, Spring Force. I know this is more than four but I hope this helps :)
3 0
3 years ago
The _______of force will determine the _______of acceleration.
loris [4]
ANSWER: the POWER of force will determine the SPEED of acceleration.

EXPLANATION
3 0
3 years ago
A sound wave has a frequency of 776 Hz in air and a wavelength of 0.52 m. What is the temperature of the air? Relate the speed o
OLEGan [10]

Answer:

142.7650889

Explanation:

I think the answer above is correct. So to find the velocity of the wave you can do: frequency*wavelength = velocity

in your case, the velocity is equal to 403.5m/s

so we know that the 403.52 is the total velocity of the wave

and the equation: velocity at 0 degrees Celsius * \sqrt{{T}/{273}} where T represents temperature in Kelvins = veloctity

so we set 403.52 = 327*\sqrt{{T}/{273}} and solve for T

T will then equal the degree in Kelvins

so to convert from Kelvins to degrees celsius you subtract 273 from the Kelvins value and you are left with the degrees in Celsius which equals 142.7650889 degrees Celsius

5 0
3 years ago
If we could see our own galaxy from 2 million light-years away, it would appear _________.
yaroslaw [1]

Answer:

It would appear as a flattened disk with a central bulge and spiral arms, spanning a few degrees across the sky.

Explanation:


I hope this helps! Have a great day!

Anygays-

5 0
2 years ago
A softball of mass 0.220 kg that is moving with a speed of 5.5 m/s (in the positive direction) collides head-on and elastically
Elanso [62]

Answer:

The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

Explanation:

Given that,

Mass of softball = 0.220 kg

Speed = 5.5 m/s

(a). We need to calculate the velocity of the target ball

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

0.220\times5.5+m_{2}\times0=0.220\times(-3.9)+m_{2}v_{2}

1.21=-0.858+m_{2}v_{2}

m_{2}v_{2}=2.068....(I)

The velocity approach is equal to the separation of velocity

u_{1}-u_{2}=v_{2}-v_{1}

5.5-0=v_{2}-(-3.9)

v_{2}=1.6\ m/s

(b). We need to calculate the mass of the target ball

Now, Put the value of v₂ in equation (I)

m_{2}\times1.6=2.068

m_{2}=\dfrac{2.068}{1.6}

m_{2}=1.29\ kg

Hence, The velocity and mass of the target ball are 1.6 m/s and 1.29 kg.

3 0
3 years ago
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