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vekshin1
3 years ago
12

An object is dropped from a height of 25 meters. At what velocity will it hit the ground? A. 7.0 meters/second B. 11 meters/seco

nd C. 22 meters/second D. 49 meters/second E. 70 meters/second
Physics
1 answer:
Basile [38]3 years ago
4 0
Final^{2}=Initial^{2}+2ad \\ x^{2}=0^{2}+2(9.8)(25) \\ x^{2}=490 \\ x=22.13 \\ C
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0.01 s<br> It asks me about the scientific notation
notsponge [240]

Answer:

Scientific notation of 0.01 is 1×10^-2

Explanation:

8 0
2 years ago
(b) If you decrease the length of the pendulum by 25%, how does the new period TN compare to the old period T?
malfutka [58]

Answer:

The new period will be reduced by 50%

Explanation:

The period of pendulum is given by;

T= 2\pi\sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{T}{2\pi} )^2 = {\frac{L}{g}}\\\\\frac{T^2}{4\pi ^2} = {\frac{L}{g}}\\\\T^2(\frac{g}{4\pi ^2}) = L\\\\ \frac{g}{4\pi ^2}= \frac{L}{T^2}\\\\\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}

When the length is decreased by 25%, the new length L₂ is given by;

L₂ = 25/100(L₁)

L₂ = 0.25L₁

\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{T_1^2L_2}{L_1} \\\\T_N^2 = \frac{T^2(0.25L_1)}{L_1}\\\\ T_N^2 =0.25T^2\\\\T_N = \sqrt{0.25T^2}}\\\\T_N = 0.5 T

Thus, the new period will be reduced by 50%

8 0
3 years ago
What is free fall? Explain it in brief.​
xxTIMURxx [149]
 · free fall is any motion of a body where gravity is the only forceacting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.

3 0
3 years ago
I NEED HELP WITH THE LAST QUESTION PLS HELP!! (The one below 8)
maksim [4K]

Answer:

I. 6 cells .

II. Series connection.

Explanation:

I. Determination of the number of cells needed.

From the question given above,

Total voltage (V) = 9 V

1.5 V = 1 cell

Number of cells needed =?

The number of cells needed to make the 9V battery can be obtained as follow:

1.5 V = 1 cell

Therefore,

9 V = 9 V × 1 cell / 1.5 V

9 V = 6 cells

Thus, 6 cells of 1.5 V each is needed

II. Determination of the connection line

Total voltage (Vₜ) = 9 V

Cell 1 (V₁) = 1.5 V

Cell 2 (V₂) = 1.5 V

Cell 3 (V₃) = 1.5 V

Cell 4 (V₄) = 1.5 V

Cell 5 (V₅) = 1.5 V

Cell 6(V₆ ) = 1.5 V

For parrall connection:

Vₜ = V₁ = V₂ = V₃ = V₄ = V₅ = V₆

9 V = 1.5 V =... = 1.5 V

For series connection:

Vₜ = V₁ + V₂ + V₃ + V₄ + V₅ + V₆

9 = 1.5 + 1.5 + 1.5 + 1.5 + 1.5 + 1.5

9 V = 9 V

From the illustration above, we can see that series connection of each cells will give a total volt of 9 V unlike the parallel connection which resulted to 1.5 V.

Therfore, the cells should be arranged in series connection

8 0
2 years ago
A golf ball is dropped from rest from a height of 9.50m. It hits the pavement, then bounces back up, rising just 5.70m before fa
marta [7]

Answer:

Explanation:

Given

height from which ball is dropped h_1=9.5\ m

and it rises to a height of h_2=5.7\ m

A person caught the ball in mid-way i.e. at a height of h_0=1.2\ m from pavement

time taken to reach the bottom is given by

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

here initial velocity is zero i.e.

h_1=0+\frac{1}{2}gt_1^2

t_1=\sqrt{\frac{2h_1}{g}}

Similarly to reach of  height h_2 time taken is t_2

t_2=\sqrt{\frac{2h_2}{g}}

The ball is caught in mid-way i.e. ball travel a distance of h_3=5.7-1.2=4.5\ m

time taken is t_3=\sqrt{\frac{2h_3}{g}}

total time taken t=t_1+t_2+t_3

t=\sqrt{\frac{2h_1}{g}}+\sqrt{\frac{2h_2}{g}}+\sqrt{\frac{2h_3}{g}}

t=\sqrt{\frac{2\cdot 9.5}{9.8}}+\sqrt{\frac{2\cdot 5.7}{9.8}}+\sqrt{\frac{2\cdot 4.5}{9.8}}

t=3.429\ s

total time =3.429 s

4 0
3 years ago
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