d=vi*t+(1/2)gt²
d=11 m
g=9.8 m/s²
vi=0 m/s
11 m=0 m/s*t+(1/2)9.8 m/s²t²
11 m=4.9 m/s²t²
t²=11 m / 4.9 m/s²
t=√(11 m / 4.9 m/s²)=1.489... s≈1.5 s
Answer: the time the sone is in flight is 1.5 s
The word that could fit to this is Text Mining. This word also referred to as text data mining, roughly equivalent to text analytics, a process of deriving high-quality information from text. This high quality information derived through the devising of patterns and trends through means such as statistical patter learning.
Answer:
The water is stored in ice sheets and as snow
Explanation:
Temperature reduces with an increase in altitudes. The standard laps rate is 6.5°C per 1,000 m gained in elevation
At very high elevations, therefore, the air is usually very cold such that when an elevation of 4,500 meters is reached at the equator, it is possible to observe snowfall and the water remain temporarily stored on the surface of the mountain as ice and snow
Speed of any freely falling object is always same. Provided, both are left to fall from the same height. If you perform this experiment in a perfect vacuum or near vacuum laboratory, both of them will reach ground with same velocity this is because there is no resistance to their motion. This is always true no matter where you go and perform this experiment.
It can be easily proved from conservation of mechanical energy. Why conserving energy? because there are no forces acting on the freely falling objects other than conservative force(mg).