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Arlecino [84]
3 years ago
7

The mass of a bronze statue is 15,000 g. The density of bronze is about 8 g/cm^3. What is the volume of the bronze statue?

Mathematics
1 answer:
Annette [7]3 years ago
8 0

Answer:1875cm^3

Step-by-step explanation:

Volume = mass/density

15,000/8=1875

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The largest angle is a triangle is 110°. Of the remaining two angles, one is 4° less than the other angle. Find the
Masja [62]

Answer:

Do 180-110=70 Then have it where 70/2=35. 35+4=39, 35-4=31, so the three angles are 39, 110, and 31.

Step-by-step explanation:

7 0
3 years ago
Dennis and Ivy share some sweets between them in the ratio 7:4 Dennis got 42 sweets. How many does ivy get
MrRa [10]

Answer:

Ivy = 24

Step-by-step explanation:

Given

Dennis : Ivy = 7 : 4

Required

Determine the amount of sweet Ivy gets when Dennis = 42

We have:

Dennis : Ivy = 7 : 4 and

Dennis = 42

Substitute 42 for Dennis in Dennis : Ivy = 7 : 4

42 : Ivy = 7 : 4

Convert to fraction

\frac{42}{Ivy} = \frac{7}{4}

Cross Multiply:

Ivy * 7 = 42 * 4

Divide through by 7

\frac{Ivy * 7}{7} = \frac{42 * 4}{7}

Ivy = \frac{42 * 4}{7}

Ivy = 6* 4

Ivy = 24

6 0
3 years ago
Enter "1" into cell A1. What do you get for the mean and the MAD of the data set
igor_vitrenko [27]
Ya totally your cool bro
7 0
3 years ago
Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).
sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

(p^4-q^4)(p^4+q^4)\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}

Therefore, the expression can be simplified as;

p^8-q^8

Alternatively, using the theorem of difference of two squares, which is

a^2-b^2=(a-b)(a+b)

Hence,

p^8-q^8=(p^4)^2-(q^4)^2

7 0
1 year ago
An exponential function f(x) = ab^xpasses through the points (0, 2) and (3, 54). What are the values of a and
Vsevolod [243]

Answers:

a = 2

b = 3

=======================================================

Explanation:

Plug in x = 0 and y = 2 to find that

y = a*b^x

2 = a*b^0

2 = a*1

2 = a

a = 2

Then plug in x = 3 and y = 54 to determine the value of b

y = a*b^x

y = 2*b^x

54 = 2*b^3

2b^3 = 54

b^3 = 54/2

b^3 = 27

b = (27)^(1/3)

b = 3

So we have y = a*b^x update to y = 2*3^x

7 0
3 years ago
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