Answer:
The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.
Explanation:
A molar heat of vaporization of 40.66 kJ / mol means that 40.66 kJ of heat needs to be supplied to boil 1 mol of water at its normal boiling point.
To know the amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure, the number of moles represented by 3.11 g of water is necessary. Being:
the molar mass of water is:
H₂O= 2* 1 g/mole + 16 g/mole= 18 g/mole
So: if 18 grams of water are contained in 1 mole, 3.11 grams of water in how many moles are present?
moles of water= 0.1728
Finally, the following rule of three can be applied: if to boil 1 mole of water at its boiling point it is necessary to supply 40.66 kJ of heat, to boil 0.1728 moles of water, how much heat is necessary to supply?
heat= 7.026 kJ
<u><em>The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.</em></u>
The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
We can see that every 1 mole of ethanol we will get 2 mole of CO₂.
So 6.0 mol of ethanol we will get = 6.0 × 2.0
= 12 mol of CO₂
Thus from the above conclusion we can say that The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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The pH of a substance can only be determined when it is
a) dried in a powder
b) frozen
c) dissolved in water
d) heated
It’s frozen
B
Answer:
Explanation:
Calculate the pH of a hydrochloride acid solution, HCl, whose hydronium ion (H3O)+ concentration is 8.29 X 10-4 M.
Note: answer should have three significant figures
The atomic mass of titanium is 47.88 u.
The average atomic mass of Ti is the <em>weighted average</em> of the atomic masses of its isotopes.
We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).
Thus,
0.0800 × 45.953 u = 3.676 u
0.0730 × 46.952 u = 3.427 u
0.7380 × 47.948 u = 35.386 u
0.0550 × 48.948 u = 2.692 u
0.0540 × 49.945 u =<u> 2.697 u
</u>
_________TOTAL = 47.88 u
