The symptom and sign which indicate placenta previa here is Pinless vaginal bleeding.
Placenta previa is a condition where the placenta is covering the cervix or it is attached close to the cervix.
In various times of pregnancy, bleeding may occur. It can not be a serious complication. The cause of the bleeding may depend on the amount of pain or the time of bleeding in pregnancy.
In the first trimester, bleeding may occur and may be due to ectopic pregnancy, miscarriage, implantation of the placenta in the uterus or infection.
Bleeding in late pregnancy lets say twenty weeks can be due to placenta previa or placental abruption.
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Answer:
The correct answer is option d.
Explanation:
Based on the given question, the genotype of the male parent is aa, the genotype of the female parent is Aa, and the genotype of the offspring is AAa, showing trisomy characteristics. In the given case, the existence of two A chromosomes shows that the chromosomes non-disjunction at the time of gametogenesis have taken place in the female as she is the only one possessing A allele. Hence, it can be concluded that the disjunction is maternal in characteristic.
The duplication of chromosomes takes place at the time of the S-phase of meiosis. Thus, after going through S-phase, the karyotype of the cell will be AAaa (maternal gametogenesis), this set of the chromosome is termed as homologous pair, and the pair of AA or aa is termed as sister chromatids.
The meiotic disjunction takes place in two phases. First, in meiosis I disjunction, in this separation of homologous chromosomes takes place, that is, the maternal cell AAaa get differentiated into aa and AA daughter cells. Secondly, in meiosis II disjunction, the separation of sister chromatids takes place into two independent chromosomes, that is, the formation of two cells each comprising chromosome A from the AA cell and the formation of two cells each with chromosome a from the aa cell.
Thus, the phenomenon of non-disjunction would have taken place at the time of meiosis II in the case of a female gamete to exhibit two A chromosomes. Hence, the correct answer is option d.
Answer:
An individual whose genotype is heterozygous cannot be for the recessive
Explanation:There are two possible genotypes either homozygous dominant or heterozygous dominant. For a charecter there can be two gene .One is recessive and other one is dominant. In presence of the dominant gene the recessive gene of the same character cannot express . IF recessive gene is homozygous then only it will express .Therefore for the individual it is heterozygous for the dominant
