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-Dominant- [34]
3 years ago
7

In which situation is the object experiencing unbalanced forces?

Physics
1 answer:
s2008m [1.1K]3 years ago
6 0

B. A car slowing as it reaches a stop light

Explanation:

According to Newton's second law, the net force exerted on an object is equal to the product between its mass and its acceleration:

F=ma

where

F is the net force

m is the mass of the object

a is its acceleration

This means that when an object is experiencing unbalanced forces (F\neq 0), it must have a non-zero acceleration. Therefore, let's analyze the different options:

A. A box resting on a horizontal floor  --> FALSE. Here the acceleration is zero, so no unbalanced forces.

B. A car slowing as it reaches a stop light  --> TRUE. Since the car is slowing down, its velocity is changing, so the acceleration is non-zero and there are unbalanced forces.

C. A car with its cruise control set to 50 mph  --> FALSE. Here the velocity is constant, so no acceleration and no unbalanced forces.

D. A rocket sitting on the launch pad --> FALSE. Here the rocket is stationary, so no acceleration, and no unbalanced forces.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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stealth61 [152]

Answer:

C = 16544.35\, USD

Explanation:

The annual electricity cost is:

C = (\frac{1}{0.93} )\cdot(75\, h.p.)\cdot(0.746\, kW)\cdot(2500\,h)\cdot(\frac{3600\,s}{1\,h} )\cdot(\frac{1\,kWh}{3600\,kJ} )\cdot (0.11\,\frac{USD}{kWh} )

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3 years ago
Plz answer #2 plz this is 8th grade science / physics
MrRissso [65]
All you need is your science book
5 0
3 years ago
Which is required for
vaieri [72.5K]

Answer:

You need (B) Two substances in direct contact with one another to have conduction.

I hope this helped at all.

5 0
3 years ago
Calculate the period of a satellite orbiting the Moon, 98 kmkm above the Moon's surface. Ignore effects of the Earth. The radius
beks73 [17]

Answer:

3.6*10^18s

Explanation:

To find the period of the satellite

We need to apply kephler's third law

Which is

MP² = (4π²/G) d³

d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km

where M= mass of the moon = 7.3x10^22kg

P=period

G=newtonian gravatational constant= 6.67x10^-11

To find the Period solve for P

P = √[(4π²/G M)xd³]

P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]

= 3.6*10^18s

6 0
3 years ago
How can hypotheses best be tested
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In order for a hypothesis to be tested, and experiment needs to be designed.

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