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user100 [1]
3 years ago
11

Please help!! giving a lot of points

Physics
1 answer:
Readme [11.4K]3 years ago
7 0

Question 1.

  • mass = 4500 kg
  • potential energy (p.e) = 67500 J

now, we know :

=》

p.e =  mgh

=》

67500 = 4500 \times 10 \times h

=》

67500 = 45000 \times h

=》

h =  \dfrac{67500}{45000}

=》

h = 1.5 \: m

note : if we take acceleration due to gravity as 9.8, then height = 1.53 m

Question 2.

  • mass = 4500 kg
  • kinetic energy = 63000 j

we know,

=》

k.e =  \dfrac{1}{2} mv {}^{2}

=》

63000 =  \dfrac{1}{2}  \times 4500 \times  {v}^{2}

=》

{v}^{2}  =  \dfrac{63000 \times 2}{4500}

=》

{v}^{2}  = 28

=》

v =  \sqrt{28}

=》

v = 2 \sqrt{7} \:  \:  ms {}^{ - 1}

or

=》

5.29 \:  \: ms {}^{ - 1}

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Answer:

True

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Answer:

I = W / 4π R_{s}²,   P = W / 2π c R_{s}², Io /I_{earth} = 10⁴  

Explanation:

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Since the emitted power is constant and has a value of W for this case, let's look for the area of ​​the sphere on the surface of the sun

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           I_{earth} = W / 4π r²

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