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Ipatiy [6.2K]
4 years ago
9

Would you expect to find a high or low level of resistance in a copper wire and why?

Physics
1 answer:
marysya [2.9K]4 years ago
4 0
Low. Copper has relatively high conductivity.
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Suppose that an object is moving along a vertical line. Its vertical position is given by the equation L(t) = 2t3 + t2-5t + 1, w
Tatiana [17]

Answer:

The average velocity is

266\frac{m}{s},274\frac{m}{s} and 117\frac{m}{s} respectively.

Explanation:

Let's start writing the vertical position equation :

L(t)=2t^{3}+t^{2}-5t+1

Where distance is measured in meters and time in seconds.

The average velocity is equal to the position variation divided by the time variation.

V_{avg}=\frac{Displacement}{Time} = Δx / Δt = \frac{x2-x1}{t2-t1}

For the first time interval :

t1 = 5 s → t2 = 8 s

The time variation is :

t2-t1=8s-5s=3s

For the position variation we use the vertical position equation :

x2=L(8s)=2.(8)^{3}+8^{2}-5.8+1=1049m

x1=L(5s)=2.(5)^{3}+5^{2}-5.5+1=251m

Δx = x2 - x1 = 1049 m - 251 m = 798 m

The average velocity for this interval is

\frac{798m}{3s}=266\frac{m}{s}

For the second time interval :

t1 = 4 s → t2 = 9 s

x2=L(9s)=2.(9)^{3}+9^{2}-5.9+1=1495m

x1=L(4s)=2.(4)^{3}+4^{2}-5.4+1=125m

Δx = x2 - x1 = 1495 m - 125 m = 1370 m

And the time variation is t2 - t1 = 9 s - 4 s = 5 s

The average velocity for this interval is :

\frac{1370m}{5s}=274\frac{m}{s}

Finally for the third time interval :

t1 = 1 s → t2 = 7 s

The time variation is t2 - t1 = 7 s - 1 s = 6 s

Then

x2=L(7s)=2.(7)^{3}+7^{2}-5.7+1=701m

x1=L(1s)=2.(1)^{3}+1^{2}-5.1+1=-1m

The position variation is x2 - x1 = 701 m - (-1 m) = 702 m

The average velocity is

\frac{702m}{6s}=117\frac{m}{s}

5 0
3 years ago
What is the velocity of a 750 kg object at a height of 0m if it’s ME is 3590J?
Cloud [144]

Answer:

Sorry for this question

7 0
3 years ago
Transcranial magnetic stimulation (TMS) is a noninvasive method for studying brain function, and possibly for treatment as well.
lubasha [3.4K]

Answer:

525 V

Explanation:

A = Area = 1.75\times 10^{-2}\ m^2

\dfrac{dB}{dt} = Rate of change of magnetic field = 3\times 10^4\ T/s (assumed)

Induced electromotive force is given by

E=A\dfrac{dB}{dt}\\\Rightarrow E=1.75\times 10^{-2}\times 3\times 10^{4}\\\Rightarrow E=525\ V

The induced electromotive force is 525 V

3 0
3 years ago
The solar noon solar radiation values at the top of the atmosphere above maun are 1366 wm−2 on february 2 and 1074 wm−2 on augus
PilotLPTM [1.2K]

You haven't stated any numbers showing that the intensity of solar radiation at the surface is lower than at the top of the atmosphere. Your data only show that the value at the top of the atmosphere is different on different dates.

From our vast experience, however, we do know that the solar intensity at the surface IS lower than it is at the top of the atmosphere, simply because the atmosphere absorbs some solar radiation ... different amounts of it at different wavelengths.

That's the main reason, for example, why the sky is red at sunrise and sunset and blue the rest of the day, and why the temperature of the air is so much higher than 3° absolute, and why we aren't broiled by X-rays all day. Also the reason why it's worth the tremendous cost and makes such a difference to build astronomical observatories on mountain tops and in low-Earth-orbit, instead of in convenient deep valleys.

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3 years ago
Function do lappet which faced vultures serve in a temperate grassland
vfiekz [6]
Um this doesn't make since to me since you did not clearly state your awnser
7 0
3 years ago
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