Answer:
c) 2.02 x 10^16 nuclei
Explanation:
The isotope decay of an atom follows the equation:
ln[A] = -kt + ln[A]₀
<em>Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope</em>
[A] = Our incognite
k is constant decay:
k = ln 2 / Half-life
k = ln 2 / 4.96 x 10^3 s
k = 1.40x10⁻⁴s⁻¹
t is time = 1.98 x 10^4 s
[A]₀ = 3.21 x 10^17 nuclei
ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]
ln[A] = 37.538
[A] = 2.01x10¹⁶ nuclei remain ≈
<h3>c) 2.02 x 10^16 nuclei</h3>
Answer: 2 s
Explanation: In order to solve this problem we have to use the formule of the final speed getting with a constant acceleration, it is given by;
Vfinal=Vo+a*t where Vo is zero.
so then t=Vfinal/a = (10 m/s)/5 m/s^2= 2 s
Answer:
Explanation:
Given
Inclination 
Distance of landing point 
Considering athlete to be an Projectile
range of projectile is given by
where u=launch velocity
(b)If u is increased by 8% then
new velocity is 
