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Masja [62]
4 years ago
13

Neurons in our bodies carry weak currents that produce detectable magnetic fields. A technique called magnetoencephalography, or

MEG, is used to study electrical activity in the brain using this concept. This technique is capable of detecting magnetic fields as weak as 1.0 10-15 T. Model the neuron as a long wire carrying a current and find the current it must carry to produce a field of this magnitude at a distance of 3.6 cm from the neuron.
Physics
1 answer:
Stolb23 [73]4 years ago
3 0

Answer:

I = (1.80 × 10⁻¹⁰) A

Explanation:

From Biot Savart's law, the magnetic field formula is given as

B = (μ₀I)/(2πr)

B = magnetic field = (1.0 × 10⁻¹⁵) T

μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

r = 3.6 cm = 0.036 m

(1.0 × 10⁻¹⁵) = (4π × 10⁻⁷ × I)/(2π × 0.036)

4π × 10⁻⁷ × I = 1.0 × 10⁻¹⁵ × 2π × 0.036

I = (1.80 × 10⁻¹⁰) A

Hope this Helps!!!

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Explanation:

<em>Law of conservation of energy states that the energy of a system is always constant. </em>

In other words, we can say that energy can neither be created nor destroyed.

Mechanical energy (E) is the sum of the potential energy (U) and the kinetic energy (K) of the freely falling body. Therefore, <em><u>E=K+U=constant.</u></em>

5 0
3 years ago
A pottery wheel, initially at rest, is assumed to be a uniform disk of mass 3.0 kg and radius 20.0 cm. A 25.0 N force is applied
miv72 [106K]

Answer:

a) 83.33 rad/s^2

b) 2500 rad/s

c) 6187.5 rad

Explanation:

Given data:

radius of wheel = 20.0 cm

mass of wheel = 3.0 kg

force = 25 N

a) angular acceleration

we know torque is given as

T = I \times \alpha

F\times R = I \times \alpha

F\times R = \frac{1}{2} mR^2 \times \alpha

solving for angular acceleration \alpha

\alpha = \frac{2F}{mR} = \frac{2*25}{3*0.2} = 83.33 rad/s^2

b)  angular velocity

duartion of force applied = 30.0 sec

\omega_{30} = \omega_0 +alpha t

                      = o + 83.33 *30 = 2500 rad/sec

c) angular displacement

\theta_{15} = = \omega_0 +\frac{1}{2} alpha t_{15}^2 = 0 + \frac{1}{2} 83.33 \times 15^2

\theta_{30} = \omega_0 +\frac{1}{2} alpha t_{30}^2 = 0 + \frac{1}{2} 83.33 \times 30^2

\Delta \theta = \theta_{30} - \theta_{15}

\Delta \theta = 6187.5 rad

3 0
3 years ago
Calculate:<br> The time taken for a plane to travel<br> 3,000 km at a speed of 200 m/s
Alborosie

Time = (distance) / (speed)

Distance = 3,000 km  =  3,000,000 meters

Speed = 200 m/s

Time = (3,000,000 m) / (200 m/s)

Time = <em>15,000 seconds</em>

That's 4 hours 10 minutes

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kiruha [24]
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-- Charges with different signs attract each other.

-- This is called the "electrostatic force".

-- There's another set of forces called "magnetic forces", but

-- there's no such thing as "electromagnetic force".
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3 years ago
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