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Masja [62]
3 years ago
13

Neurons in our bodies carry weak currents that produce detectable magnetic fields. A technique called magnetoencephalography, or

MEG, is used to study electrical activity in the brain using this concept. This technique is capable of detecting magnetic fields as weak as 1.0 10-15 T. Model the neuron as a long wire carrying a current and find the current it must carry to produce a field of this magnitude at a distance of 3.6 cm from the neuron.
Physics
1 answer:
Stolb23 [73]3 years ago
3 0

Answer:

I = (1.80 × 10⁻¹⁰) A

Explanation:

From Biot Savart's law, the magnetic field formula is given as

B = (μ₀I)/(2πr)

B = magnetic field = (1.0 × 10⁻¹⁵) T

μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

r = 3.6 cm = 0.036 m

(1.0 × 10⁻¹⁵) = (4π × 10⁻⁷ × I)/(2π × 0.036)

4π × 10⁻⁷ × I = 1.0 × 10⁻¹⁵ × 2π × 0.036

I = (1.80 × 10⁻¹⁰) A

Hope this Helps!!!

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To solve this problem it is necessary to apply the concepts related to the concept of overlap and constructive interference.

For this purpose we have that the constructive interference in waves can be expressed under the function

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d = Distance of slit to screen

m = Number of order which represent the number of repetition of the spectrum

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At the same time the distance on the screen from the central point, would be

sin\theta = \frac{y}{d}

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PART A ) From the previous equation if we arrange to find the angle we have that

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Answer:

Explanation:

Given

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f=\frac{v}{\lambda }

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f=\frac{343}{1}=343\ Hz

For next frequency which will cause destructive interference is

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\lambda =\frac{1}{3}\ m

frequency corresponding to this is

f_2=\frac{343}{\frac{1}{3}}=1029\ Hz

for m=2

3.5-3=\frac{5}{2}\cdot \lambda

\lambda =\frac{1}{5}\ m

Frequency corresponding to this wavelength

f_3=\frac{343}{\frac{1}{5}}

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Period is the answer

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now the distance before they stop with respect to each other is given by

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Explanation:

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