Answer:
5.42 s
Explanation:
Using the equation of motion,
v = u + at ..................... Equation 1,
Where v = Final velocity, u = initial velocity, a = acceleration, t = time.
Making t the subject of the equation,
t = (v-u)/a ....................... Equation 2
Note: When the the bicycle is brought to a complete stop, the final velocity of the bicycle is 0 m/s and the bicycle is decelerating.
Given: v = 0 m/s, u = 6.5 m/s, a = - 1.2 m/s² ( decelerating).
Substituting into equation 2
t = (0-6.5)/-1.2
t = -6.5/-1.2
t = 5.42 s.
Hence the time take for the cyclist to bring the bicycle to complete stop = 5.42 s
