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alexandr1967 [171]
3 years ago
9

With an average acceleration of â1.2 m/s² , how long will it take a cyclist to bring a bicycle with an initial speed of 6.5 m/s

to a complete stop?
Physics
1 answer:
julsineya [31]3 years ago
6 0

Answer:

5.42 s

Explanation:

Using the equation of motion,

v = u + at ..................... Equation 1,

Where v = Final velocity, u = initial velocity, a = acceleration, t = time.

Making t the subject of the equation,

t = (v-u)/a ....................... Equation 2

Note: When the the bicycle is brought to a complete stop, the final velocity of the bicycle is  0 m/s and the bicycle is decelerating.

Given: v = 0 m/s, u = 6.5 m/s, a = - 1.2 m/s² ( decelerating).

Substituting into equation 2

t = (0-6.5)/-1.2

t = -6.5/-1.2

t = 5.42 s.

Hence the time take for the cyclist to bring the bicycle to complete stop = 5.42 s

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What is the difference between a bound orbit and an unbound orbit around the sun?
Anit [1.1K]

Answer:

Explanation:

The difference between a bound orbit and an unbound orbit around the sun is that:

An object on a bound orbit pursues the same way around the Sun again and again, while an object on an unbound orbit moves toward the Sun only a single time and afterward stays away forever &  never returns.

8 0
3 years ago
An apple with a mass of 0.95 kilograms hangs from a tree branch 3.0 meters above the ground.if it falls to the ground, what is t
NeTakaya
KE=1/2mv^2
KE=1/2x0.95x3=1.425
5 0
4 years ago
A basketball is shot from 2 meters up at an angle of 60° above the x axis at an initial velocity of 9 m/s. What is the maximum h
Nikitich [7]

Hope this helps a little

initial distance up = 2

initial velocity component up = 9 sin 60 = 7.79

v = 9 sin 60 - 9.8 t

when v = 0, we are there

9.8 t = 7.79

t = .795 seconds to top

h = 2 + 7.79(.795) - 4.9(.795^2)

7 0
4 years ago
Read 2 more answers
Provide an example of when momentum is conserved and explain your answer you can get 10 PTS if answered with a good explaination
dezoksy [38]

Answer:

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

Explanation:

<u>Conservation of Momentum </u>

The total momentum of a system of two particles is

p=m_1v_1+m_2v_2

Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now

p'=m_1v_1'+m_2v_2'

The momentum is conserved if no external forces are acting on the system, thus

m_1v_1+m_2v_2=m_1v_1'+m_2v_2'

Let's put some numbers in the problem and say

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

(8)(12)+(6)(4)=(8)(-6)+(6)(28)

96+24=-48+168

120=120

It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s

4 0
3 years ago
What is the maximum weight a boat can hold if a boat can displace 60.5ml?
Valentin [98]

Answer:

a. 60.5 kg

Explanation:

Given data,

The maximum water a boat can displace is, 60.5 ml

According to the principle of buoyancy, the weight of the floating body is equal to the weight of the liquid displaced.

Under standard temperature and pressure, a unit mass of water equals one liter.

If a boat can displace a maximum of 60.5 ml of water, then it can hold a mass of a maximum of 60.5 kg of mass.

6 0
3 years ago
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