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alexandr1967 [171]
3 years ago
9

With an average acceleration of â1.2 m/s² , how long will it take a cyclist to bring a bicycle with an initial speed of 6.5 m/s

to a complete stop?
Physics
1 answer:
julsineya [31]3 years ago
6 0

Answer:

5.42 s

Explanation:

Using the equation of motion,

v = u + at ..................... Equation 1,

Where v = Final velocity, u = initial velocity, a = acceleration, t = time.

Making t the subject of the equation,

t = (v-u)/a ....................... Equation 2

Note: When the the bicycle is brought to a complete stop, the final velocity of the bicycle is  0 m/s and the bicycle is decelerating.

Given: v = 0 m/s, u = 6.5 m/s, a = - 1.2 m/s² ( decelerating).

Substituting into equation 2

t = (0-6.5)/-1.2

t = -6.5/-1.2

t = 5.42 s.

Hence the time take for the cyclist to bring the bicycle to complete stop = 5.42 s

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Answer:25000/23 N/M^2

Explanation:

P=f/A=30/(0.23×0.12)=25000/23

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3 years ago
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?​
Xelga [282]
<h2><u>Question</u><u>:</u><u>-</u></h2>

Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?

<h2><u>Answer:</u><u>-</u></h2>

<h3>Given,</h3>

=> Force applied by Ryan = 10N

=> Distance covered by the book after applying force = 30 cm

<h3>And,</h3>

30 cm = 0.3 m (distance)

<h3>So,</h3>

=> Work done = Force × Distance

=> 10 × 0.3

=> 3 Joules

\small \boxed{work \: done \:  by \: Ryan \:  = 3 \: Joules}

4 0
3 years ago
Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

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Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
What element x is most likely to react to form the compound xf5?
djyliett [7]
<span>antimony. It has +3,+5,-3 so yeah. the others carbon+2,+4,-4, chlorine +1,+5,+7,-1 but -1 is the most often so it isn't Cl, calcium +2.</span>
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