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3 years ago

Evaluate the expression when y=6 5y+1 someone help please!

Mathematics

1 answer:

ruslelena [56]3 years ago

3 0

Answer:

Step-by-step explanation:

5y + 1

Putting value of y

5(6) + 1

= 30 + 1

= 31

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Please help me with this #5

shepuryov [24]

$\text{Given that,}\\\\a_1 = 10~ \text{ and}~ a_n = a_{n-1} -4~\text{for}~ n\geq 2\\\\a_2 = a_{2-1} -4 = a_1 -4 = 10 -4 = 6\\\\a_3 = a_{3-1} - 4=a_2 -4 = 6 -4 =2\\\\a_4 = a_{4-1} -4 = a_3 -4 = 2 -4 = -2\\\\\text{The first four terms are:}~ 10,~ 6,~ 2~, -2$

8 0

2 years ago

The x - intercept of the function f(x) = x2 + 4x - 12 is:

Assoli18 [71]

Answer:

C) (-6,0)(2,0)

For x-intercept, f(x) = 0:

${ \tt{ {x}^{2} + 4x - 12 = 0 }} \\ { \tt{(x - 2)(x + 6) = 0}}$

8 0

3 years ago

Read 2 more answers

Find the measure of < B

Vinvika [58]

The measure of angle b is 25°.

Solution:

Given data:

The "L" shape angle is a right angle.

Right angle is splitted by another line and two angles are formed.

One angle is 65° and the other angle is b.

Let us find the other angle b.

65° + m∠b = 90°

Subtract 65° from both sides of the equation.

m∠b = 90° – 65°

m∠b = 25°

Hence the measure of angle b is 25°.

6 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

The vertices of a triangle are as follows: (4,) (6,7) and (8,0) If you dilate the triangle by a scale factor of 3, what are the

Paraphin [41]

Given:

Consider the vertices of the triangle are (4,4) (6,7) and (8,0).

The triangle is dilated by a scale factor of 3.

To find:

The vertices of the new triangle after dilation.

Solution:

If a figure is dilated by scale factor k with origin as the center of dilation, then the rule of dilation is:

$(x,y)\to (kx,ky)$

The given figure is dilated by scale factor 3 with origin as the center of dilation, then the rule of dilation is:

$(x,y)\to (3x,3y)$

Let the vertices of the triangle are A(4,4), B(6,7) and C(8,0).

Using this rule of dilation, we get

$A(4,4)\to A'(3(4),3(4))$

$A(4,4)\to A'(12,12)$

Similarly,

$B(6,7)\to B'(3(6),3(7))$

$B(6,7)\to B'(18,21)$

And,

$C(8,0)\to C'(3(8),3(0))$

$C(8,0)\to C'(24,0)$

The vertices of the new triangle are (12,12), (18,21), (24,0).

Therefore, the correct option is 4.

7 0

3 years ago