Question

What is the volume of solution (in mL) produced when 91.80g of Mg(OH)2 are used

Answer 1

Answer:  The volume of solution is 2248 ml

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

moles of $Mg(OH)_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{91.80g}{58.32g/mol}=1.574mol$

Now put all the given values in the formula of molality, we get

$0.7=\frac{1.574\times 1000}{V_s}$

$V_s=\frac{1.574\times 1000}{0.7}=2248ml$

Therefore, the volume of solution is 2248 ml