1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andreas93 [3]
3 years ago
7

How are atoms formed?

Chemistry
1 answer:
Greeley [361]3 years ago
6 0

Answer:

atoms were created after the Big Bang 13.7 billion years ago. As the hot, dense new universe cooled, conditions became suitable for quarks and electrons to form. Quarks came together to form protons and neutrons, and these particles combined into nuclei.

Explanation:i hope that helps

You might be interested in
What is the mole fraction of KCI in a
Margaret [11]

Answer:

Mole fraction of KCl = 0.4056

Explanation:

We'll begin by calculating the number of mole of each compound. This can be obtained as follow:

For NaCl:

Mass NaCl = 0.564 g

Molar mass of NaCl = 58.44 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 0.564 / 58.44

Mole of NaCl = 0.0097 mole

For KCl:

Mass KCl = 1.52 g

Molar mass of KCl = 74.55 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1.52 / 74.55

Mole of KCl = 0.0204 mole

For LiCl:

Mass LiCl = 0.857 g

Molar mass of LiCl = 42.39 g/mol

Mole of LiCl =?

Mole = mass /Molar mass

Mole of LiCl = 0.857 / 42.39

Mole of LiCl = 0.0202 mole

Next, we shall determine the total mole in the mixture. This can be obtained as follow:

Mole of NaCl = 0.0097 mole

Mole of KCl = 0.0204 mole

Mole of LiCl = 0.0202 mole

Total mole =?

Total mole = Mole of NaCl + Mole of KCl + Mole of LiCl

Total mole = 0.0097 + 0.0204 + 0.0202

Total mole = 0.0503 mole

Finally, we shall determine the mole fraction of KCl in the mixture. This can be obtained as follow:

Mole of KCl = 0.0204 mole

Total mole = 0.0503 mole

Mole fraction of KCl =?

Mole fraction of KCl = Mole of KCl /Total mole

Mole fraction of KCl = 0.0204 / 0.0503

Mole fraction of KCl = 0.4056

4 0
3 years ago
Read 2 more answers
All amino acids have two ionizable groups (an alpha-amino group with pKa~9.3, and an alpha-carboxyl group with pKa~2.2). Lysine
raketka [301]
The answer will be 9.1 % 
8 0
3 years ago
1.______ structure is achieved when a protein folds into a compact, three-dimensional between side-chain R groups of amino acids
kondor19780726 [428]

Answer:

The answer to your question is:

Explanation:

1._<u>Terciary</u>__ structure is achieved when a protein folds into a compact, three-dimensional between side-chain R groups of amino acids.

2._<u>Primary</u>___ structure is the sequence of amino acids in a protein.

3._<u>Secondary</u>___ structure describes the alpha helices and beta-sheets that are formed by hydrogen bonding between backbone atoms located near each other in the polypeptide chain.

4._<u>Quaternary</u>___ structure is the result of two or more protein subunits assembling to form a larger, biologically active protein complex.

5 0
4 years ago
What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

3 0
3 years ago
The tendency for an object at rest to remain at rest is?
cestrela7 [59]
Newtons First Law... <span>Newton's first law of motion - sometimes referred to as the law of </span>inertia<span>. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an </span>unbalanced<span> force.</span>
6 0
4 years ago
Other questions:
  • How is oxygen separated from other substances nearby?
    11·1 answer
  • What is most likely true of an atom with a mass of 15 amu?
    13·1 answer
  • Select the correct answer from each drop-down menu.
    11·1 answer
  • Where is energy stored in living sytems
    7·1 answer
  • Calculate the numbers of mL in 0.603 L
    5·1 answer
  • The solubility product for an insoluble salt with the formula mx3 is written as __________, where s is the molar solubility.
    6·1 answer
  • Calculate the molarity of a solution made by
    15·1 answer
  • A solution in which the pH is 1.6 would be described as
    7·1 answer
  • What is the simplest type of pure substance
    5·1 answer
  • A buffer solution is prepared by adding NaH2PO4 to a solution of H3PO4 (phosphoric acid).
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!