Answer:
78.96 g of NaC2H3O2
Explanation:
We are given;
- Volume of the solution as 350 mL
- Molarity of the solution as 2.75 M
- Molar mass of the solute NaC2H3O2 as 82.04 g/mol
We are required to determine the mass of the solute;
First we determine the number of moles;
Moles = Molarity × Volume
Therefore;
Moles of the solute = 2.75 M × 0.350 L
= 0.9625 moles
Second, we determine the mass
Mass = Moles × Molar mass
= 0.9625 moles × 82.04 g/mol
= 78.9635 g
= 78.96 g
Therefore, the mass of NaC2H3O2 needed is 78.96 g
In a balanced chemical equation, the numbers of individual particles and the numbers of moles of particles are represented by the COEFFICIENTS.
:-) ;-)
The KE can be solve using the formula:
ke = 0.5 mv^2
where m is the mass of the object
v is the velocity
ke = 0.5 ( 2 kg ) ( 5 m/s)^2
ke = 25 J
the GPE can be solved using the formula:
GPE = mgh
where m is the mass
g is the acceleration due to gravity ( 9.81 m/s^2)
h is the height
GPE = ( 4 kg)(9.81 m/s^2)( 40 m)
GPE = 392.4 J
Answer:
0 587 mL
Explanation:
First we convert 180 grams of HCl into moles, using its molar mass:
- 180 g ÷ 36.46 g/mol = 4.94 mol HCl
Now we can <u>use the number of moles and the given concentration to calculate the required volume</u>, applying the <em>definition of molarity</em>:
- Molarity = moles / liters
- Liters = Moles / molarity
- 4.94 mol / 8.40 M = 0.588 L
Finally we <u>convert liters into milliliters</u>:
The closest answer is option C, 587 mL.
