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givi [52]
4 years ago
7

When magnesium metal is heated in air it begins to release large amounts of heat and light. What kind of a reaction is this an e

xample of?
A. a fusion reaction


B. a fission reaction


C. a combustion reaction


D. an endothermic reaction
Physics
2 answers:
kolezko [41]4 years ago
6 0
C. Combustion reaction.

These reaction are exothermic.

The reactions are:

2Mg + O2 -----> 2MgO

3Mg + N2 ------> Mg3N2
nignag [31]4 years ago
3 0
C. Combustion.
Any reaction that produces light or fire is a combustion reaction.
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Be sure to answer all parts. Without stratospheric ozone (O3), harmful solar radiation would cause gene alterations. Ozone forms
Ratling [72]

Answer:

for C-Cl  bond \lambda_1=3.66\times 10^{-9}\ m

for O-O bond \lambda_2=2.43\times 10^{-9}\ m

Explanation:

  • We have the bond enegy for C-Cl, BE_1=327\ kJ.mol^{-1}= 327000\times 1.66\times 10^{-22}\ J\ per\ molecule
  • bond enegy for C-Cl, BE_2=494\ kJ.mol^{-1}= 494000\times 1.66\times 10^{-22}\ J\ per\ molecule

<u>Now as we know the energy of electromagnetic waves is given by:</u>

E=h.\nu

here E = BE

<u>Then for C-Cl:</u>

327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1

\nu_1=8.18733\times 10^{16}\ Hz

Now wavelength:

\lambda_1=\frac{c}{\nu_1}

\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}

\lambda_1=3.66\times 10^{-9}\ m

<u>For O2:</u>

494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2

\nu_2=1.236863\times 10^{17}\ Hz

Now wavelength:

\lambda_2=\frac{c}{\nu_2}

\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}

\lambda_2=2.43\times 10^{-9}\ m

8 0
3 years ago
An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi
poizon [28]

Answer:

image is vertical at distance -203.62 cm

magnification is 2.110

Explanation:

given data

n = 1.51

distance u = 96.5 cm

concave radius r1 = 24 cm

convex radius r2 = 19.1 cm

to find out

final image distance and magnification

solution

we will apply here lens formula to find focal length f

1/f = n-1 ( 1/r1 - 1/r2)   .......................1

put here all value

1/f = 1.51 -1 ( -1/24 + 1/19.1)

f = 183.43

so from lens formula

1/f = 1/v + 1/u     .............................2

put here all value and find v

1/183.43 = 1/v + 1/96.5

so

v = −203.62 cm

so here image is vertical at distance -203.62 cm

and

magnification are = -v /u

magnification =  203.62 / 96.5

magnification is 2.110

3 0
4 years ago
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