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alexandr402 [8]
3 years ago
14

I need help with this question

Physics
1 answer:
allsm [11]3 years ago
4 0

Answer:

500

Explanation:

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1) Which is an example of two-dimensional motion?
telo118 [61]

Answer: C

Explanation:

A bird flying in the air is 3D motion as the bird move up, down, right, left all the possible direction. A leaf falling from a tree is also a 3D motion because a leaf never fall in absolute vertical manner. A lady bug crawling on a soccer ball also 3D. If lady bug crawling on a plane like floor then it is 2D but now lady bug crawling on soccer ball which is in spherical shape so it is also 3D motion. Only train travelling along a track is 2D because train cannot move up and down and the track of train is in a plane. So it is 2D motion.  

3 0
3 years ago
NO LINKS!!!!!! Help its urgent, PLEASE HELP!!!!!!!!!!!!!!!!
Likurg_2 [28]

Answer:

I think ur answer would be B

Explanation:

srry if wrong

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7 0
3 years ago
What is the difference between deviation and incidence
yKpoI14uk [10]

Explanation:

<u><em>Deviation</em><em> </em><em>:</em><em> </em></u><em> </em>

It means the difference between a expected value of a measurement or an observation vs the actual value.

<em><u>Incidence</u></em><em><u> </u></em><em><u>:</u></em>

A straight line, ray of light, etc.., hits a surface at a point.

3 0
3 years ago
Read 2 more answers
Diffusion and osmosis are forms of passive transport.<br><br> True<br> False
pishuonlain [190]

Answer:

True. Diffusion and osmosis are forms of passive transport.

Explanation:

In diffusion, particles move from an area of higher concentration to one of lower concentration until equilibrium is reached.

In osmosis, a semipermeable membrane is present, so only the solvent molecules are free to move to equalize concentration.

8 0
3 years ago
Read 2 more answers
A battery with an internal resistance ofrand an emf of 10.00 V is connected to a loadresistorR=r. As the battery ages, the inter
yanalaym [24]

Answer:

The current is reduced to half of its original value.

Explanation:

  • Assuming we can apply Ohm's Law to the circuit, as the internal resistance and the load resistor are in series, we can find the current I₁ as follows:

        I_{1} = \frac{V}{R_{int} +r_{L} }

  • where Rint = r and RL = r
  • Replacing these values in I₁, we have:

       I_{1} = \frac{V}{R_{int} +r_{L} } = \frac{V}{2*r} (1)

  • When the battery ages, if the internal resistance triples, the new current can be found using Ohm's Law again:

       I_{2} = \frac{V}{R_{int} +r_{L} } = \frac{V}{(3*r) +r} = \frac{V}{4*r}  (2)

  • We can find the relationship between I₂, and I₁, dividing both sides, as follows:

        \frac{I_{2} }{I_{1} } = \frac{V}{4*r} *\frac{2*r}{V} = \frac{1}{2}

  • The current when the internal resistance triples, is half of the original value, when the internal resistance was r, equal to the resistance of the load.  
7 0
3 years ago
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