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1 year ago

I have a picture of the question I need help with,

Physics

1 answer:

eduard1 year ago

7 0

Given:

The initial velocity of the object, v=30 m/s

a_t=0

a_c≠0

The time period is Δt.

To find:

The right conclusion among the given choices.

Explanation:

a_t represents the tangential accleration on the object and a_c represents the centripetal acceleration on the object.

The centripetal acceleration is the acceleration that keeps the object in its circular path. The centripetal force only changes the direction of the velocity and not the magnitude.

Thus the magnitude of the velocity of the object remains the same after a time interval of Δt. But the direction of the velocity of the object will be changed and will be unknown after Δt seconds.

Final answer:

Thus the object will be traveling at 30 m/s in some unknown direction.

Therefore, the correct answer is option a.

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Consider an object on a rotating disk a distance r from its center, held in place on the disk by static friction. Which of the f

SVEN [57.7K]

Answer:

A) False

B) False

C) True

D) True

E) True

Explanation:

A) The formula for tangential speed v in term of angular speed ω and radius of rotation r is

$v = \omega r$

So if the angular speed is constant and 0, the tangential speed is also 0. A) is false

B) False because of the centripetal acceleration:

$a_c = \omega^2 r$

C) True because of the formula for tangential acceleration in term of angular acceleration α is

$a_t = \alpha r$

D) True because same as D), if it has angular acceleration, it would have a tangential acceleration. Also from B) the centripetal acceleration will come with time as soon as angular speed is generated by angular acceleration.

E) True and same explanation as from B)

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3 years ago

A truck enters a typical runaway lane with a speed of 57.5 mph ( 25.7 m/s ). Use the work-energy theorem to find the minimum coe

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Answer:

Work done by friction force= change in total Energy

so,

W= (friction force)*d= (mu*N)*(35)

so,

mu*m*g*35= 1/2*m*v^2

so,

mu= 0.5*(25.7)^2/(9.81*35)

solving it,

mu = 0.9618

Explanation:

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3 years ago

Placing the north pole of a magnet near the south pole of another magnet results in:

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Answer:

An attractive force between the magnets. A is the correct answer if it was the north pole facing another north pole magnet the answer would have been a repulsive force between the magnets because the north pole of a magnet does not attract instead it separates from each other which is a repulsive force the best answer is A.

Explanation:

the southern pole of a magnet is a positive force while the northern pole of a magnet is negative .

Note: Magnet can attract each other only when they are facing the opposite directions a north pole will attract a south pole; the magnets pull on each other. But the two north poles will push each other away.

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3 years ago

2. Who bombarded molybdenum with atomic number (Z=42) with fast moving<br>neutrons?<br>

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Answer:

This question appears incomplete

Explanation:

This question appears incomplete, however Molybdenum-99 (⁹⁹Mo) is produced by bombarding Molybdenum-98 (⁹⁸Mo) with fast moving neutrons (¹₀n) as shown below

⁹⁸₄₂Mo + ¹₀n ⇒ ⁹⁹₄₂Mo + ⁰₀γ

This reaction is a nuclear caption reaction (which occurs in a nuclear reactor) for the production of Molybdenum-99 (⁹⁹Mo) which serves as a "precursor" for the production of medically viable/ Clinical Grade Technutium-99m (⁹⁹Tc) through Ion-exchange technique.

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4 years ago

Give two examples of human activity that affect the earth systems

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Humans affect the eath by burning fossil fuels

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3 years ago