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Kipish [7]
4 years ago
6

Which compund will conduct electricity when it is dissolved in water​

Chemistry
1 answer:
NNADVOKAT [17]4 years ago
7 0
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ CuSO4 (copper sulfate.) This is because it is an ionic compound

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Why do cactuses have roots if they already restore water inside themselfs
Alinara [238K]

Answer:

To stay on the ground, say during a storm, the roots help keep the plant anchored

Explanation: "hope this helps"

7 0
4 years ago
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Which of these factors influences air temperature?
Ksju [112]

Answer:

D

Explanation:

3 0
3 years ago
A plastic wading pool has a circumference of 12.56 feet. Which procedure will help you
RoseWind [281]

The diameter of  the pool is 4

Explanation:

To calculate the diameter we must write the values given in the question, here

The circumference of the pool is given as C=12.56 feet.

To calculate the diameter of the pool,

If radius is given, Multiply the radius by 2

If Circumference is given divide the circumference by Pi (π)

the constant value for  Pi (π)=3.14

Diameter(D)= C/π

12.56/3.14

=4

The diameter for the plastic wading pool is 4

7 0
3 years ago
Al + 02 --&gt; Al 2 0 3
nata0808 [166]

The coefficient for aluminium is 4.

Explanation:

We have the following chemical reaction:

Al + O₂ → Al₂O₃

In order to balance the chemical equation the number of the atoms entering the reaction should be equal to the number of atoms leaving the reaction.

2 Al + 3/2 O₂ → Al₂O₃

However we need integer numbers so we multiply everything with 2.

4 Al + 3 O₂ → 2 Al₂O₃

The coefficient for aluminium is 4.

Learn more:

about balancing chemical equations

brainly.com/question/8062886

brainly.com/question/238492

#learnwithBrainly

5 0
3 years ago
How many mL of 0.563 M HNO3 are needed to dissolve 7.83 g of BaCoz? 2HNO3(aq) + BaCO3(s) — Ba(NO3)2(aq) + H2O(1) + CO2(8) mL
Lorico [155]

Answer:

Volume of HNO₃ required = 140 mL

Explanation:

Given data:

Molarity of HNO₃ = 0.563 M

mass of BaCO₃ = 7.83 g

Volume of HNO₃ = ?

Solution:

First of all we will write the balance chemical equation

2HNO₃ +  BaCO₃   →    Ba(NO₃)₂  + H₂O + CO₂

Number of moles of BaCO₃ = mass /  molar mass

Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol

Number of moles of BaCO₃ = 0.04 mol

Now we compare the moles of  BaCO₃  and HNO₃ .

                   BaCO₃       :     HNO₃  

                      1              :       2

                     0.04       :       2×0.04 = 0.08 mol

Volume of HNO₃ required = number of moles / Molarity

Volume of HNO₃ required =  0.08 mol / 0.563 mol/L

Volume of HNO₃ required =  0.14 L

0.14 × 1000 = 140 mL

8 0
3 years ago
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