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Vinvika [58]
2 years ago
14

Which element’s atoms have the greatest average number of neutrons?

Chemistry
2 answers:
andrezito [222]2 years ago
8 0
The correct answer is tellurium
algol [13]2 years ago
6 0

Answer:

not sure but i guess it's Tellurium

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Calculate the atomic mass of chromium it’s composition is 83.79% with a mass of 51.94 amu; 9.50% with a mass of 52.94 Amu; 4.35%
Elina [12.6K]

<span><span>Convert the percentages into decimals (you can do that by dividing the percent by 100), then multiply that by its corresponding mass to find its relative amount/ contribution to the atomic mass of chromium. After doing so, add all of the obtained values together to get the average mass.

</span> 83.79% = .08379
9.50% = .095
4.35% = .0435
2.36% = .0236

Average mass of chromium = 0.8379(51.94) + 0.095( 52.94) + 0.0435(49.95) + 0.0236(53.94)

Answer: 52amu

P.S. never forget units
</span>
8 0
2 years ago
3
Mashcka [7]

Answer:

It is 34

Explanation:

4 0
2 years ago
ASPA!!!! How could a scientist determine what elements are present in a distant star by looking at its absorption spectrum?
8_murik_8 [283]

Answer:

Spectroscopy

Explanation:

They can determine its composition based on these wavelengths. The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy

8 0
2 years ago
Rank the following compounds from highest boiling to lowest boiling. To rank items as equivalent, overlap them.
Olegator [25]

1-pentanol > 1-butanol > 1-chlorobutane > pentane

Explanation:

You my find in the attached picture the structures of the compounds, names and also the variation of their boiling points.

Alcohols have higher boiling points because they form hydrogen bonds between the molecules.

Learn more about:

boiling points in organic compounds

brainly.com/question/2153588

#learnwithBrainly

7 0
2 years ago
The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
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