Answer:
0.51g
Explanation:
Given parameters:
Volume of nitrogen gas = 744mL
Unknown:
Mass of sodium metal produced = ?
Solution:
Let us assume that the gas, nitrogen was collected at STP which is the standard temperature and pressure, we can easily find its number of moles.
Number of moles = 
since the gas volume given is 744mL = 0.744mL
Therefore input the variables;
Number of moles = 
= 0.03moles
Now that we know the number of moles of the gas, let us revisit the reaction equation:
2NaN₃ → 2Na + 3N₂
It good to ensure that the reaction is balanced;
3 mole of nitrogen gas is produced with 2 moles of Na
0.03 mole of nitrogen gas will be produce with 
= 0.02mole
So;
Using;
mass = number of moles x molar mass
let us solve for the mass of Na;
molar mass of Na = 23g/mol
mass = 0.02 x 23 = 0.51g
<span>HCl + MnO2 → MnCl2 + H2O + Cl2
To balance this reaction, we have to have an exact number of electrons of each element on both sides. So it will turn into:
4HCl + MnO2 </span>→ MnCl2 + 2H2O + Cl2
From that, we could see that the coefficient for the HCL is 4.
Answer:
C₁₀H₁₆O
Explanation:
Molecular formula can be determined from parent peak by using rule of thirteen.
Rule of Thirteen:
First divide the parent peak value by 13 as,
= 152 ÷ 13
= 11.69
Now, multiply 13 by 11,
= 13 × 11 (here, 11 specifies number of carbon atoms)
= 143
Now subtract 143 from 152,
= 152 - 143
= 9
Add 9 into 11,
= 9 + 11
= 20 (hydrogen atoms)
So, the rough formula we have is,
C₁₁H₂₀
Now, add one Oxygen atom to above formula and subtract one Carbon and 4 Hydrogen atoms as these numbers are equal to atomic mass of Oxygen atom as,
C₁₁H₂₀ -------O--------> C₁₀H₁₆O
Calculate Hydrogen deficiency index as,
HDI = (2x + 2 - y) / 2
where,
x = C atoms
y = H atoms
HDI = [2(10) + 2 - 16] / 2
HDI = (20 + 2 - 16) / 2
HDI = (22-16) / 2
HDI = 6 / 2
HDI = 3
It means, Camphor contains 1 double bond and two rings. As, HDI of double bond is 1 and HDI of one ring is 1.
Answer:
The answer is 196.96655.
Explanation:
We assume you are converting between grams Gold and mole.
You can view more details on each measurement unit:
molecular weight of Gold or mol
The molecular formula for Gold is Au.
The SI base unit for amount of substance is the mole.
1 grams Gold is equal to 0.0050770041918285 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Gold and mole.
Type in your own numbers in the form to convert the units!
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