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Helen [10]
4 years ago
5

What would happen if mass is continually added to a 1.4 solar mass neutron star?

Physics
1 answer:
andrey2020 [161]4 years ago
8 0
Eventually wouldn't it collapse in on itself and create black hole.
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Which of the following is an example of heat convection?
lora16 [44]
I believe it’s a liquid inside a beaker on a hot Bunsen burner (c)

This is because : Everyday Examples of Convection
Boiling water - The heat passes from the burner into the pot, heating the water at the bottom. Then, this hot water rises and cooler water moves down to replace it, causing a circular motion. Radiator - Puts warm air out at the top and draws in cooler air at the bottom.

Not sure if it’s right tho!
8 0
4 years ago
Read 2 more answers
Please help me people
saveliy_v [14]

Answer :

(1) The density of asphalt is, 1200kg/m^3

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

<u>Part 1 :</u>

As we are given:

Mass of block = 90 kg

Volume of block = 0.075m^3

Formula used :

\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}

Now put all the given values in this formula, we get:

\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3

Thus, the density of asphalt is, 1200kg/m^3

<u>Part 2(a) :</u>

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

<u>Part 2(b) :</u>

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}

2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}

\text{Mass of aluminium}=15.59kg

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

7 0
3 years ago
Read 2 more answers
Which three elements have the most similar chemical properties?
Montano1993 [528]

Answer:

c

Explanation:

all are metals

3 0
3 years ago
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Does a car accelerate when it goes around a corner at a constant speed?
Evgen [1.6K]
Yes, it does. Acceleration is defined as the rate of change of velocity. Velocity is the rate of change of position with a given direction i.e. speed with direction.So even though the speed of the turning car is constant the velocity is not. This means that the velocity is changing, and the rate of change of velocity is called acceleration. Hence, the car is accelerating.
6 0
4 years ago
A string along which waves can travel is 4.36 m long and has a mass of 222 g. The tension in the string is 60.0 N. What must be
lora16 [44]

Answer:

frequency is 195.467 Hz

Explanation:

given data

length L = 4.36 m

mass m = 222 g = 0.222 kg

tension T = 60 N

amplitude A = 6.43 mm = 6.43 × 10^{-3} m

power P = 54 W

to find out

frequency f

solution

first we find here density of string that is

density ( μ )= m/L ................1

μ = 0.222 / 4.36  

density μ is 0.050 kg/m

and speed of travelling wave

speed v = √(T/μ)       ...............2

speed v = √(60/0.050)

speed v = 34.64 m/s

and we find wavelength by power that is

power = μ×A²×ω²×v  /  2     ....................3

here ω is wavelength put value

54 = ( 0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 )   /  2

0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 = 108

ω² = 108 / 7.160  × 10^{-5}

ω = 1228.16 rad/s

so frequency will be

frequency = ω / 2π

frequency = 1228.16 / 2π

frequency is 195.467 Hz

7 0
4 years ago
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