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3 years ago

What is 500 rounded to the nearest hundred

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

Answer: 500

Step-by-step explanation:

The reason why it's 500 because it's already been rounded. 500 stays as 500 bc numbers 4 and below goes down to 0 when rounding. When rounding 0-4 with just the ones place it stays the same.

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The temperature readings from a thermocouple in a furnace fluctuate according to a cumulative distribution function,

Oliga [24]

Answer:

$P(x$

$P(x>808.40) = 0.58$

$P(x\le805.40\ or\ x\ge 808.40) = 0.85$

Step-by-step explanation:

Given:

$F(x) = \left\{\begin{array}{ll}{0} &; {x$

Solving (a): P(x < 810)

To solve this, we make use of:

$P(x$

Because

$800^\circ C \le 810 \le 820^\circ C$

So:

$F(x) = 0.05 * 810 -40$

$F(x) = 40.5 -40$

$F(x) = 0.5$

Hence:

$P(x$

Solving (b): P(x < 800)

To solve this, we make use of:

$P(x$

Because:

$x < 800^\circ C$

So:

$P(x$

Solving (c): P(x > 808.40)

Here, we make use of complement rule:

$P(x>808.40) = 1 - P(x \le 808.40)$

Where:

$P(x\le808.40) = 0.05x - 40$

$P(x\le808.40) = 0.05*808.40 - 40$

$P(x\le808.40) = 0.42$

So:

$P(x>808.40) = 1 - 0.42$

$P(x>808.40) = 0.58$

Solving (d) The probability that the temperature lies outside 805.60 and 808.40

First, we calculate the probability that it lies within.

This is represented as:

$P(805.40 < x < 808.40)$

This is calculated using:

$P(805.40 < x < 808.40) = F(808.40) - F(805.40)$

$P(805.40 < x < 808.40) = 0.05*808.40-40 - (0.05*805.40-40)$

$P(805.40 < x < 808.40) = 0.42 - (0.27)$

$P(805.40 < x < 808.40) = 0.42 - 0.27$

$P(805.40 < x < 808.40) = 0.15$

Using complement rule, the required probability is:

$P(x\le805.40\ or\ x\ge 808.40) = 1 - 0.15$

$P(x\le805.40\ or\ x\ge 808.40) = 0.85$

5 0

3 years ago

What is 0.66666666666 as a fraction

stellarik [79]

To turn $0.(6)=0.6666...$ into a fraction you should do such steps:

1 step. Set up an equation by representing the repeating decimal with a variable. Using your example, you will let x represent the repeating decimal 0.(6), so you have x=0.666... .

2 step. Identify how many digits are in the repeating pattern, or n digits. Multiply both sides of the equation from Step 1 by $10^n$ to create a new equation. Again, using your example, you see that the repeating pattern consists of just one digit: 6. Now multiply both sides of the equation by $10^1 = 10$ . Thus, you have $10x = 10 \cdot 0.666...$ or $10x = 6.666....$ .

3 step. Subtract the equation in Step 1 from the equation in Step 2. Notice that when we subtract these equations, our repeating pattern drops off. Therefore, $10x-x=6.666...-0.666...\\ 9x=6$ .

4 step. You now have an equation that you can solve for x and simplify as much as possible, using x as a fraction: $9x = 6$ . If you divide both sides by 9, you get $x=\dfrac{6}{9}$ . When simplified, you get that $x=\dfrac{2}{3}$ .