Answer:
23. 
24. 
25. 
26. 
27. 
28. 
Step-by-step explanation:
To solve these i used SOHCAHTOA

23.
Find the missing side using Tangent



24.
Find the missing side using Tangent



25.
Find the missing side using Tangent



26.
Find the missing side using Tangent



27.
Find the missing side using Tangent



28.
Find the missing side using Tangent



Answer:

Step-by-step explanation:
We need to integrate the given expression. Let I be the answer .
- Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
- Now , Rewrite using du and u .

Since 42% of packages are being shipped via priority mail, we can safely assume the other 58% are not. 150 x 0.58 is 87.
Answer: m< MIH is 34°
M< AVM is 70°
And the angle of the obtuse angle formed at the intersection of AV and HI is 104°
Step-by-step explanation: starting with m<MIH, AH is parallel to MI, so that would make the same angle H has the same for I. (34°)
Next is m<AVM. The angle of m<LAH is 110°. So the angle of m<HAV (because it's supplementary of it) is 70 (110+70=180). Which makes m<AVM 70° since it's vertical to each other.
Since we got those answers, the next one you just plug it in, and the answer would be 104°
Green crescent should be 11
2+2+11=15
Pink trapezoid should be 15
30-15=15
15=15