Answer:
The methane gives Neptune the same blue color as Uranus.
Explanation:
Answer:
150.8 J
Explanation:
The heat released by the copper wire is given by:
![Q=mC_s \Delta T](https://tex.z-dn.net/?f=Q%3DmC_s%20%5CDelta%20T)
where:
m = 10.0 g is the mass of the wire
Cs = 0.377 j/(g.C) is the specific heat capacity of copper
is the change in temperature of the wire
Substituting into the equation, we find
![Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J](https://tex.z-dn.net/?f=Q%3D%2810.0%20g%29%280.377%20J%2FgC%29%28-40.0%5E%7B%5Ccirc%7D%29%3D-150.8%20J)
And the sign is negative because the heat is released by the wire.
Answer:
82.25 moles of He
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 10 L
Mass of He = 0.329 Kg
Temperature (T) = 28.0 °C
Molar mass of He = 4 g/mol
Mole of He =?
Next, we shall convert 0.329 Kg of He to g. This can be obtained as follow:
1 Kg = 1000 g
Therefore,
0.329 Kg = 0.329 Kg × 1000 g / 1 Kg
0.329 Kg = 329 g
Thus, 0.329 Kg is equivalent to 329 g.
Finally, we shall determine the number of mole of He in the tank. This can be obtained as illustrated below:
Mass of He = 329 g
Molar mass of He = 4 g/mol
Mole of He =?
Mole = mass / molar mass
Mole of He = 329 / 4
Mole of He = 82.25 moles
Therefore, there are 82.25 moles of He in the tank.
105 miles because you have to use the gif arable
Simply, apply the formula
![E = \frac{1}{2}mv^{2}](https://tex.z-dn.net/?f=%20E%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D%20)
and insert the values of m = mass, v = velocity and E = Energy.
The result will be
![72J = \frac{1}{2}m(12m/s)^{2}](https://tex.z-dn.net/?f=72J%20%3D%20%20%5Cfrac%7B1%7D%7B2%7Dm%2812m%2Fs%29%5E%7B2%7D%20%20)
, m = 1 kg