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DedPeter [7]
3 years ago
8

Discuss the factors that are used to determine power.

Physics
2 answers:
True [87]3 years ago
5 0
<span>The factors that are used to determine power are:
Voltage,current and the power factor.

</span><span>Power = Voltage x Current x K
Watts = Volts x Amps x Power Factor</span>
posledela3 years ago
3 0

Answer : current , voltage and resistance

Explanation:  Three factors are used to power.

Current , voltage and resistance

When we find the power then we need the voltage, current and resistance.

We use the ohm's law and find the power

Firstly we will use the ohm's law

V = I \times R

Now, the power is

P = I\times V...(i)

Put the value of V in equation (i)

P = I^{2}\times R

This is the formula of power and factors of the power is current , voltage and resistance. Watt is the unit of power.



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3 years ago
If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial accelerat
Ugo [173]

Answer:

The acceleration of the proton is 2.823 x 10¹⁷ m/s²

The acceleration of the electron is 5.175 x 10²⁰ m/s²

Explanation:

Given;

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mass of proton, m_p = 1.67 x 10⁻²⁷ kg

mass of electron, m_e = 9.11 x 10⁻³¹ kg

The attractive force between the two charges is given by Coulomb's law;

F = \frac{k(q_p)(q_e)}{r^2}

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/c²

F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N

Acceleration of proton is given by;

F = ma

F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2

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F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2

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3 years ago
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