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3 years ago

How much of the universe is believed to consist of ordinary atoms that can be detected?

1 answer:

4 0

The universe believed to be has no limit in space and the elements, molecules and different kind of gases are found in this area. So the percentage of that is believed that and ordinary atom can be detected is C. 3% i hope you understand my answer.

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A student found the rock shown above and weighed it to determine its mass. What steps should the student take to find its densit

musickatia [10]

find its density is the key so good luck buddy

7 0

3 years ago

Describe what is happening to the speed during the period (I). 0s - 10s __________________________________________________ (II).

aleksley [76]

Answer:

- There was a constant acceleration at 0 to 10s

- There was a zero acceleration at 10 to 25s

- There was a constant deceleration at 25 to 30s

Explanation:

See attachment for complete question.

Solving (a): What happens at 0s to 10s

There was a constant acceleration and this is proven below.

At time 0, velocity = 15

At time 10, velocity = 30

This is represented as:

$(t_1,v_1) = (0,15)$

$(t_2,v_2) = (10,30)$

Acceleration (A) is the rate of change of velocity against time.

So:

$A = \frac{v_2 - v_1}{t_2-t_1}$

$A = \frac{30-15}{10 - 0}$

$A = \frac{15}{10}$

$A = 1.5$

Since the acceleration is positive, then it shows a constant acceleration.

Solving (b): What happens at 10s to 25s

There was a zero acceleration and this is because the velocity do not change.

See proof below

At time 10, velocity = 30

At time 25, velocity = 30

This is represented as:

$(t_1,v_1) = (10,30)$

$(t_2,v_2) = (25,30)$

Acceleration (A) is the rate of change of velocity against time.

So:

$A = \frac{v_2 - v_1}{t_2-t_1}$

$A = \frac{30-30}{25 - 10}$

$A = \frac{0}{15}$

$A = 0$

Solving (c): What happens at 25s to 30s

There was a constant deceleration and this is proven below.

At time 25, velocity = 30

At time 30, velocity = 0

This is represented as:

$(t_1,v_1) = (25,30)$

$(t_2,v_2) = (30,0)$

Acceleration (A) is the rate of change of velocity against time.

So:

$A = \frac{v_2 - v_1}{t_2-t_1}$

$A = \frac{0-30}{30-25}$

$A = \frac{-30}{5}$

$A = -6$

Since the acceleration is negative, then it shows a constant deceleration

4 0

3 years ago

Use 4 to 5 complete sentences, explain the concepts of beats and how beats are produces.

Wewaii [24]

Answer:

Beats is a phenomenon which occurs when two sound waves with different frequencies overlap each other.

Explanation:

When these two sound waves overlap, a third frequency is formed. The places where the two waves reinforces each other, constructive interference takes place and a louder sound is produced whereas, at points where destructive interference takes place a softer sound is produced.

These alternative loud and soft sounds are called beats.

3 0

4 years ago

What is the net force acting on a golf car travelling at a constiant speed of 5 mph?

pashok25 [27]

0 Newtons, since it's at a constant speed. Hope this helps, and Brainliest answer would be appreciated!

5 0

3 years ago

Read 2 more answers

A 8.0×104kgspaceship is at rest in deep space. Its thrusters provide a force of 1200kN. The spaceship fires its thrusters for 20

Sladkaya [172]

Answer:

Time = 40 s

It will take the spaceship 40s to coast that distance.

Explanation:

Using the impulse momentum equation;

Impulse = change in momentum

Ft = m(∆v) ........1

Given;

Force F = 1200kN

time of action t = 20s

Mass of spaceship m = 8.0×10^4 kg

∆v = change in velocity

Substituting the values into equation 1;

1200kN × 20s =8.0×10^4 kg × ∆v

∆v = 1200000×20/80000

∆v = 300 m/s

Since it was initially at rest, V0 = 0

Final velocity V2 = 300 + 0

V2 = 300m/s

Time To travel 12 km,

Time = distance/speed

Distance = 12 km = 12000m

Speed = 300m/s

Time = 12000/300

Time = 40 s

It will take the spaceship 40s to coast that distance.

4 0

3 years ago