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Murljashka [212]
2 years ago
9

How many 60-watt lamps could be connected in parallel on a 15-amp, 120-volt circuit without exceeding 80% of the rating of the c

ircuit?
Physics
1 answer:
Alborosie2 years ago
5 0

The total number of lamps is mathematically given as

N=24

<h3>What is the total number of lamps?</h3>

Question Parameters:

How many 60-watt lamps could be connected in parallel on a 15-amp, 120-volt

Generally, the equation for the Power  is mathematically given as

P=IV

Therefore

I=P/v

I=60/120

I=0.5A

Since the system does not exceed 80% of the rating

NI=I'(0.8)

N=15*0.8/0.5

N=24

In conclusion, the total number of lamps is

N=24

Read more about  Arithmetic

brainly.com/question/22568180

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Bronco the skydiver, whose mass is 100 kg experiences 200 N of air resistance. What is the acceleration of his fall? Show Work
bekas [8.4K]

Explanation:

air resistance (f) =mg

200=100g

g=200/100

g=2m/s^2

5 0
2 years ago
A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g
levacccp [35]

The actual weight of the gas = apparent weight + weight.

The actual weight = W_{A} + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = W_{A}

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/m^{2}

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  W_{A} + W

Learn more about density here: brainly.com/question/406690

8 0
2 years ago
What is the weight of a 4.2 kg bowling ball on Mars?
Nataliya [291]

What is the weight of a 4.2 kg bowling ball on Mars?

Answer:

1.59 kg

Explanation:

The formula is:

<u>F = G((Mm)/r2) </u>

F is the gravitational force between two objects,

G is the Gravitational Constant (6.674×10-11 Newtons x meters2 / kilograms2),

M is the planet's mass (kg),

m is your mass (kg), and

r is the distance (m) between the centers of the two masses (the planet's radius).

Hope this helps

--Jay

8 0
3 years ago
A rail car moving at 10m/s collides with and connect to another stationary car. What is their final velocity?
ki77a [65]

Answer:

read this it might help some

When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.

Explanation:

6 0
3 years ago
A string that is under 54.0 N of tension has linear density 5.20 g/m . A sinusoidal wave with amplitude 2.50 cm and wavelength 1
kicyunya [14]

Answer:

8.89288275 m/s

Explanation:

F = Tension = 54 N

\mu = Linear density of string = 5.2 g/m

A = Amplitude = 2.5 cm

Wave velocity is given by

v=\sqrt{\frac{F}{\mu}}\\\Rightarrow v=\sqrt{\frac{54}{5.2\times 10^{-3}}}\\\Rightarrow v=101.90493\ m/s

Frequency is given by

f=\frac{v}{\lambda}\\\Rightarrow f=\frac{101.90493}{1.8}\\\Rightarrow f=56.61385\ Hz

Angular frequency is given by

\omega=2\pi f\\\Rightarrow \omega=2\pi 56.61385\\\Rightarrow \omega=355.71531\ rad/s

Maximum velocity of a particle is given by

v_m=A\omega\\\Rightarrow v_m=0.025\times 355.71531\\\Rightarrow v_m=8.89288275\ m/s

The maximum velocity of a particle on the string is 8.89288275 m/s

5 0
2 years ago
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