Answer:
D. Banks and offices closing on sunday.
Explanation:
Church is usually on sunday and people need a day off to do it because service is about 3 hours long. When banks and offices close on this day it shows how religion has affected our lives and our culture.
1.What types of geological events or changes occur at divergent plate boundaries?
Volcanoes and minor earthquakes occur at divergent plate boundaries.
2. What types of geological events or changes occur at convergent plate boundaries? Volcanoes, earthquakes and fold mountains occur at convergent plate boundaries.
3. What types of geological events or changes occur at transform plate boundaries? Earthquakes and fold mountains occur at transform plate boundaries.
4. Explain how these geological processes and interactions have changed Earth's surface through the years. Magma from volcanoes is filled with nutrients that makes land fertile. Some earthquakes make the ground shake so violently that it destroys entire landscapes and environments. Earthquakes can also cause landslides and tsunamis, which destroy whole villages, change geology and ruin natural habitats of many living creatures. W<span>hen an earthquake happens in the middle of the ocean, it can create waves that are so large that they destroy coastlines, cities, and forests hundreds of miles away.</span>
Answer: Tangential Velocity
The tangential velocity 
is defined as the angular velocity 
by the radius 
of circular motion. As shown below:
Its name is due to the fact that this linear velocity vector is always tangent to the trajectory and is the distance traveled by a body or object in a circular movement in a period of time.
Answer: Your question is missing below is the question
Question : What is the no-friction needed speed (in m/s ) for these turns?
answer:
20.1 m/s
Explanation:
2.5 mile track
number of turns = 4
length of each turn = 0.25 mile
banked at 9 12'
<u>Determine the no-friction needed speed </u>
First step : calculate the value of R
2πR / 4 = πR / 2
note : πR / 2 = 0.25 mile
∴ R = ( 0.25 * 2 ) / π
= 0.159 mile ≈ 256 m
Finally no-friction needed speed
tan θ = v^2 / gR
∴ v^2 = gR * tan θ
v = √9.81 * 256 * tan(9.2°) = 20.1 m/s
V1 =16 m/s and V2 =24 m/s. Constant acceleration = 9.8 m/s. The range for a horizontal drop is R=V1* the square root(2h/g. R1=16 * the square root of 2*5.4/9.8. =16.796 meters. And R2= 24 * the square root of 2*5.4/9.8 = 25.194. R2 - R1 = how far apart the two vessel will be. 25.194 - 16.796 = 8.398 or 8.4 meters
