An airliner must reach a speed of 110 m/s to take off. If the length of the runway is 2.4 km and the aircraft accelerates from r
1 answer:
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Answer:
The coefficient of friction is 0.38.
Explanation:
The free body diagram is drawn below.
Let be frictional force acting in the backward direction as shown. Let the coefficient of friction be
. Let
be the normal reaction force acting on the bag.
Given:
Mass of the bag is,
Force acting at ° is
Acceleration due to gravity is,
The force F can be resolved into its components as and
Therefore,
Now, as there is no acceleration in vertical direction, therefore,
Sum of upward forces = Sum of downward forces
Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.
Therefore, backward force = forward force.
Now, frictional force is given as:
Therefore, the coefficient of friction is 0.38.
Answer:
True
Explanation:
The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.
The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.
Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.
Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.
