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BabaBlast [244]
3 years ago
13

65ml a 6M solution of HCl are needed to neutralize 82ml of NaOH of an unknown molarity.

Chemistry
1 answer:
vodomira [7]3 years ago
8 0

Answer:

A. HCl + NaOH —> NaCl + H2O

B. 4.76M

Explanation:

The equation for the reaction is given below:

HCl + NaOH —> NaCl + H2O

From the equation

nA (mole of the acid) = 1

nB (mole of the base) = 1

The following data were obtained from the question:

Ma = 6M

Va = 65mL

Mb =?

Vb = 82mL

Using MaVa/MbVb = nA/nB, the molarity of the base can be obtained as follows:

MaVa/MbVb = nA/nB

6 x 65/ Mb x 82 = 1

Cross multiply to express in linear form.

Mb x 82 = 6 x 65

Divide both side by 82

Mb = (6 x 65) /82

Mb = 4.76M

The molarity of NaOH is 4.76M

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