Ummmmmmmm...... Idk sorry
Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)
Answer is: <span>3. they conduct electricity.
1) acids taste sour, bases taste bitter.
2) acid </span><span>would react with metals and produce hydrogen gas:
Ca(s) + 2HCl(aq) </span>→ CaCl₂(aq) + H₂(g).
3) Acids and bases give ions in water solutions, so <span>they conduct electricity.
</span>
An Arrhenius base is a
substance that dissociates in water to form hydroxide ions (OH⁻<span>).
In this example lithium hydroxide is an Arrhenius base:</span>
LiOH(aq) → Li⁺(aq) + OH⁻(aq).
An Arrhenius acid is a
substance that dissociates in water to form hydrogen ions or protons (H⁺<span>).
For example hydrochloric acid: HCl(aq) → H</span>⁺(aq) + Cl⁻(aq).
4) red litmus turn blue whe base is drop on it and blue litmus turn red when acid is drop on it.
5) bases have pH greater than 7, acids have pH less than 7.
Answer:
Explanation:
Vaporization Equation => Q = m·ΔHv
m = 0.5Kg water = 500g water
ΔHv = Heat of vaporization = 540 calories/gram
∴Q = 500g x 540cal/g = 270,000 calories x 4.184 joules/cal = 1,129,680 joules = 1130 Kilojoules (3 sig. figs.)
