Question

A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 7.80 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration 1.60 times that due to gravity? (You do not need to enter any units.)

Answer 1

Answer:N=13.53 rpm

Explanation:

Given

radius $r=7.80 m$

Centripetal acceleration $a_c=1.6 g$

and centripetal acceleration $a_c=\omega ^2r$

where $\omega =angular\ velocity$

$1.6\times 9.8=\omega ^2\times 7.8$

$\omega ^2=2.0102$

$\omega =1.417 rad/s$

and  $\omega =\frac{2\pi \cdot N}{60}$

$1.417\times 60=2\pi \cdot N$

$N=13.53 rpm$