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creativ13 [48]
3 years ago
5

Which feature should a system administrator use to facilitate them? When working on opportunities, sales representatives at Univ

ersal Containers need to understand how their peers have successfully managed other opportunities with comparable products, competing against the same competitors.
A. Big deal alerts
B. Chatter groups
C. Similar opportunities
D. Opportunity update reminders
Engineering
1 answer:
il63 [147K]3 years ago
5 0

The correct answers are B & C; Chatter Groups and Similar opportunities.

Further Explanation:

Sales representatives can use chatter groups and other similar opportunities to their advantage. This can help them to understand and manage their products that are in direct competition with competitors.

A chatter group can be used to share ideas both privately and publicly. These groups can have more than 30,000 people or just 3 people, it depends on how many are interested in the topic or product. The groups can be made unlisted and by invite only and then you can see with whom you are talking to. Nonmembers can view anything written in the public and archived groups. This is a great way to see how your peers are doing with their product.

Learn more about chatter groups at brainly.com/question/4489111

#LearnwithBrainly

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Fuel filters are being replaced on a HPCR diesel
saw5 [17]

Answer:) The correct answer is B. at the end of the fuel rail.

2) The one who is correct is the Technician A.

Explanation:

7 0
3 years ago
For laminar flow over a hot flat plate, the local heat transfer coefficient decreases with distance because (select all that are
kotegsom [21]

Answer:

B. The thickness of the heated region near the plate is increasing.

Explanation:

First we know that, a boundary layer is the layer of fluid in the immediate vicinity of a bounding surface where the effects of viscosity are significant. The fluid is often slower due to the effects of viscosity. Advection i.e the transfer of heat by the flow of liquid becomes less since the flow is slower, thereby the local heat transfer coefficient decreases.

From law of conduction, we observe that heat transfer rate will decrease based on a smaller rate of temperature, the thickness therefore increases while the local heat transfer coefficient decreases with distance.

3 0
3 years ago
Methane gas is 304 C with 4.5 tons of mass flow per hour to an uninsulated horizontal pipe with a diameter of 25 cm. It enters a
Arada [10]

Answer:

a) h_c = 0.1599 W/m^2-K

b) H_{loss} = 5.02 W

c) T_s = 302 K

d) \dot{Q} = 25.125 W

Explanation:

Non horizontal pipe diameter, d = 25 cm = 0.25 m

Radius, r = 0.25/2 = 0.125 m

Entry temperature, T₁ = 304 + 273 = 577 K

Exit temperature, T₂ = 284 + 273 = 557 K

Ambient temperature, T_a = 25^0 C = 298 K

Pipe length, L = 10 m

Area, A = 2πrL

A = 2π * 0.125 * 10

A = 7.855 m²

Mass flow rate,

\dot{ m} = 4.5 tons/hr\\\dot{m} = \frac{4.5*1000}{3600}  = 1.25 kg/sec

Rate of heat transfer,

\dot{Q} = \dot{m} c_p ( T_1 - T_2)\\\dot{Q} = 1.25 * 1.005 * (577 - 557)\\\dot{Q} = 25.125 W

a) To calculate the convection coefficient relationship for heat transfer by convection:

\dot{Q} = h_c A (T_1 - T_2)\\25.125 = h_c * 7.855 * (577 - 557)\\h_c = 0.1599 W/m^2 - K

Note that we cannot calculate the heat loss by the pipe to the environment without first calculating the surface temperature of the pipe.

c) The surface temperature of the pipe:

Smear coefficient of the pipe, k_c = 0.8

\dot{Q} = k_c A (T_s - T_a)\\25.125 = 0.8 * 7.855 * (T_s - 298)\\T_s = 302 K

b) Heat loss from the pipe to the environment:

H_{loss} = h_c A(T_s - T_a)\\H_{loss} = 0.1599 * 7.855( 302 - 298)\\H_{loss} = 5.02 W

d) The required fan control power is 25.125 W as calculated earlier above

5 0
3 years ago
I really need help ASAP!!!
ValentinkaMS [17]

Explanation:

He would work on the thing like in the method you work on your question.

8 0
2 years ago
4) A steel tape is placed around the earth at the equator when the temperature is 0 C. What will the clearance between the tape
snow_lady [41]

Answer:

2102.1 m

Explanation:

Temperature at the equator = 0⁰

Radius of the earth = 6.37x10⁶

Required:

We how to find out what the clearance between tape and ground would be if temperature increases to 30 degrees.

Final temperature = ∆T = 303-273 = 30

S = 11x10^-6

The clearance R = Ro*S*∆T

=6.37x10⁶x 11x10^-6x30

= 2102.1m

Or 2.102 kilometers

Thank you

4 0
2 years ago
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