The cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors will be D. 8 cubic inches.
<h3>What is a conductor?</h3>
It should be noted that a conductor simply means a substance or material that simply allows electricity to pass through it.
From the information given, the cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors is yo be computed.
This will be:
= (4 × 6)/3
= 24/3
= 8
In conclusion, the cubic inch space that is required inside a box for 4 #6 XHHN current carrying conductors will be 8 cubic inches.
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Answer:
C)185,500 KJ
Explanation:
Given that
Latent heat fusion = 333.23 KJ/kg
Latent heat vaporisation = 333.23 KJ/kg
Mass of ice = 100 kg
Mass of water = 40 kg
Mass of vapor=60 kg
Ice at 0°C ,first it will take latent heat of vaporisation and remain at constant temperature 0°C and it will convert in to water.After this water which at 0°C will take sensible heat and gets heat up to 100°C.After that at 100°C vapor will take heat as heat of vaporisation .
Sensible heat for water Q
For water
Q=4.178 x 40 x 100 KJ
Q=16,712 KJ
So total heat
Total heat =100 x 333.23+16,712 + 60 x 2257 KJ
Total heat =185,455 KJ
Approx Total heat = 185,500 KJ
So the answer C is correct.
Answer:
Expression for output voltage = V = Vo sin wt
Explanation:
Amplitude of output voltage = Vo = 19 V
Frequency = f = 240 Hz
Now we know that
Angular frequency = w = 2 π (1 / T) = 2 π 240 = 480 π Hz
Expression for output voltage = V = Vo sin wt
Expression for output voltage = V = 19 (sin 480 π) t
Answer:
Explanation:
% Clears variables and screen
clear; clc
% Asks user for input
n = input('Total number of objects: ');
r = input('Size of subgroup: ');
% Computes and displays permutation according to basic formulas
p = 1;
for i = n - r + 1 : n
p = p*i;
end
str1 = [num2str(p) ' permutations'];
disp(str1)
% Computes and displays combinations according to basic formulas
str2 = [num2str(p/factorial(r)) ' combinations'];
disp(str2)
=================================================================================
Example: check
How many permutations and combinations can be made of the 15 alphabets, taking four at a time?
The answer is:
32760 permutations
1365 combinations
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Answer:
I am a girl want private photos
Explanation:
