Who is using welding symbols to to communicate the detailed information necessary for welders to complete the weld?

Engineering

1 answer:

muminat3 years ago

3 0

Answer: An engineer or a craftsperson

Explanation:

Welding symbols allow the engineer or draftsperson to communicate detailed information about the weld to the welder. In most cases, the welding symbol has an arrow, which points to the location on the drawing where a weld is required. The arrow is attached to a leader line that intersects with a horizontal reference line. The arrow and leader line point to the joint in question, while the weld symbol tells the welder what type of weld to do. If the weld symbol is below the reference line, the weld should be made on the same side as the arrow.

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The current at resonance in a series L-C-R circuit is 0.2mA. If the applied voltage is 250mV at a frequency of 100 kHz and the c

iVinArrow [24]

Answer:

The resistance of the circuit is 1250 ohms

The inductance of the circuit is 0.063 mH.

Explanation:

Given;

current at resonance, I = 0.2 mA

applied voltage, V = 250 mV

resonance frequency, f₀ = 100 kHz

capacitance of the circuit, C = 0.04 μF

At resonance, capacitive reactance ( $X_c$ ) is equal to inductive reactance ( $X_l$ ),

$Z = \sqrt{R^2 + (X_ l - X_c)^2} \\\\But \ X_l= X_c\\\\Z = R$

Where;

R is the resistance of the circuit, calculated as;

$R = \frac{V}{I} \\\\R = \frac{250 \ \times \ 10^{-3}}{0.2 \ \times \ 10^{-3}} \\\\R = 1250 \ ohms$

The inductive reactance is calculated as;

$X_l = X_c = \frac{1}{\omega C} = \frac{1}{2\pi f_o C} = \frac{1}{2\pi (100\times 10^3)(0.04\times 10^{-6} ) } = 39.789 \ ohms\\$

The inductance is calculated as;

$X_l = \omega L = 2\pi f_o L\\\\L = \frac{X_l}{2\pi f_o}\\\\L = \frac{39.789}{2\pi (100 \times 10^3)} \\\\L= 6.3 \ \times \ 10^{-5} \ H\\\\L = 0.063 \times \ 10^{-3} \ H\\\\L = 0.063 \ mH$