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frosja888 [35]
3 years ago
6

Who is using welding symbols to to communicate the detailed information necessary for welders to complete the weld?

Engineering
1 answer:
muminat3 years ago
3 0

Answer: An engineer or a craftsperson

Explanation:

Welding symbols allow the engineer or draftsperson to communicate detailed information about the weld to the welder. In most cases, the welding symbol has an arrow, which points to the location on the drawing where a weld is required. The arrow is attached to a leader line that intersects with a horizontal reference line. The arrow and leader line point to the joint in question, while the weld symbol tells the welder what type of weld   to do. If the weld symbol is below the reference line, the weld should be made on the same side as the arrow.

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What are some quality assurance systems
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When replacing a timing belt, many experts and vehicle manufacturers recommend that all of the following should be replaced exce
lora16 [44]

Answer:

Correct Answer:

A. water pump

Explanation:

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3 years ago
Consider casting a concrete driveway 40 feet long, 12 feet wide and 6 in. thick. The proportions of the mix by weight are given
Akimi4 [234]

Answer:

Weight of cement = 10968 lb

Weight of sand = 18105.9 lb

Weight of gravel = 28203.55 lb

Weight of water = 5484 lb

Explanation:

Given:

Entrained air = 7.5%

Length, L = 40 ft

Width,w = 12 ft

thickness,b= 6 inch, convert to ft = 6/12 = 0.5 ft

Specific gravity of sand = 2.60

Specific gravity of gravel = 2.70

The volume will be:

40 * 12 * 0.5 = 240 ft³

We need to find the dry volume of concrete.

Dry volume = wet volume * 1.54 (concrete)

Dry volume will be = 240 * 1.54 = 360ft³

Due to the 7% entarained air content, the required volume will be:

V = 360 * (1 - 0.07)

V = 334.8 ft³

At a ratio of 1:2:3 for cement, sand, and gravel respectively, we have:

Total of ratio = 1+2+3 = 6

Their respective volume will be =

Volume of cement = \frac{1}{6}*334.8 = 55.8 ft^3

Volume of sand = \frac{2}{6}*334.8 = 111.6 ft^3

Volume of gravel = \frac{3}{6}*334.8 = 167.4 ft^3

To find the pounds needed the driveway, we have:

Weight = volume *specific gravity * density of water

Specific gravity of cement = 3.15

Weight of cement =

55.8 * 3.15 * 62.4 = 10968 pounds

Weight of sand =

111.6 * 2.60 * 62.4 = 18105.9 lb

Weight of gravel =

167.4 * 2.7 * 62.4 = 28203.55 lb

Given water to cement ratio of 0.50

Weight of water = 0.5 of weight of cement

= 1/2 * 10968 = 5484 lb

4 0
3 years ago
A device that transforms electrical energy to mechanical:
xxTIMURxx [149]

Answer:

electric motor

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Explanation:

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2 years ago
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